Using a variable in fopen
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I want to run a loop that will access files from multiple folders
I used dir to retrieve the names of the folders and I want to be able to feed the names into fopen.
ex:
folder = dir('W:\Examples')
#_of_folders = numel(folder)
for i=1:#_of_folders
fid = fopen('W:\Examples\folder([i])')
...
end
How can I enter that variable into fopen? Is there a better way of achieving this?
I did take a look at this thread, but I am still having trouble.
Thank you
1 个评论
采纳的回答
Iain
2014-9-11
init = 'W:\Examples';
folder = dir(init)
for i = 1:numel(folder)
% do something with folder(i) to figure out if it's a file you want to open, or a folder you want to search, and if so:
filename = [init '\' folder(i).name]; % or filename = [init '\' folder(i).name '\' folder(i).name '.abc']; if you know that the folders contain files with the same name as the folder and a fixed extension...
% do something with filename
fid = fopen(filename,'r');
end
更多回答（1 个）
Ken Atwell
2014-9-11
You can use fullfile as a convenient way to create a full path from parts. 'folder' as returned by dir will be an array of structs -- you are interested in the 'name' field.
(Note you can't use "#" as part of a MATLAB variable name, so I've use "num_files" instead)
folder = dir('W:\Examples')
num_files = numel(folder)
for i=1:num_files
fid = fopen(fullfile('W:\Examples', folder(i).name))
...
end
3 个评论
Ken Atwell
2014-9-12
I'm not quite following, but you can pass an arbitrary number of pieces to fullpath:
fid = fopen(fullpath('W:\Examples', folder(i).name, 'folder', 'file'))
Andrew
2014-9-23
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