Using a variable in fopen

 init = 'W:\Examples';
 folder = dir(init)
 for i  = 1:numel(folder)
  % do something with folder(i) to figure out if it's a file you want to open, or a folder you want to search, and if so:
 filename = [init '\' folder(i).name]; % or  filename = [init '\' folder(i).name '\' folder(i).name '.abc']; if you know that the folders contain files with the same name as the folder and a fixed extension...
 % do something with filename
 fid =  fopen(filename,'r');
 end

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Answer 2

Ken Atwell 2014-9-11

1
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https://ww2.mathworks.cn/matlabcentral/answers/154332-using-a-variable-in-fopen#answer_151328

在 MATLAB Online 中打开

You can use fullfile as a convenient way to create a full path from parts. 'folder' as returned by dir will be an array of structs -- you are interested in the 'name' field.

(Note you can't use "#" as part of a MATLAB variable name, so I've use "num_files" instead)

 folder = dir('W:\Examples')
 num_files = numel(folder)
 for i=1:num_files
     fid = fopen(fullfile('W:\Examples', folder(i).name))
     ...
 end

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Ken Atwell 2014-9-12

在 MATLAB Online 中打开

I'm not quite following, but you can pass an arbitrary number of pieces to fullpath:

fid = fopen(fullpath('W:\Examples', folder(i).name, 'folder', 'file'))

Andrew 2014-9-23

Thank you, this worked perfectly

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