index exceed matrix dimensions

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seprienna 2014-9-11

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评论： seprienna 2014-9-11

hello folks, I'm trying to run 2 different dimensional vectors by using weighted regions with a chosen factor. can I get some expert opinion on identify the error,please. your help is gratefully appreciated.Many thanks in advance.

   x=train_data; % 882 x2 double
  z=test_data;  %882 x 8 double
  distance_max=[];
for h=1:size(x)    
 for kb=1:size(z)
        kk=x(:,h);
        gg=z(:,kb); <-- this is where the error appeared
weightsum=0;
ww  = [0, 1,1,1,1,1,0,0,1,1,1,1,1,0,1,1,2,1,2,1,1,2,4,4,0,4,4,2,1,1,1,1,1,1,1,0,1,2,2,2,1,0,0,0,1,1,1,0,0];   
length=18;
region = size(x,1)/length; 
    for e=1:region
      e_start = (e -1) * length+1 ;
      e_end = e_start + length-1 ; 
     xpart=kk(e_start:e_end);   
     zpart = gg (e_start:e_end);
   D1 = pdist2(xpart',zpart','chisq')*ww(e);
   distance_max=[distance_max,D1];
  weightsum=weightsum+D1;
    end
  results(h,k)={weightsum};    
  end
 end

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seprienna 2014-9-11

编辑：seprienna 2014-9-11

million apologies for the confusion adam. I was using the y for a different data but in this experiment, i'm using 'x' and 'z'. Can you kindly point out how can i avoid the dimension error please.

Rick Rosson 2014-9-11

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Two lines above the line that caused the error:

for kb=1:size(y)

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采纳的回答

Rick Rosson 2014-9-11

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编辑：Rick Rosson 2014-9-11

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Please try changing the line

for kb=1:size(y)

to the following:

for kb=1:size(z)

Also, please correct the issue with size described in the answer provided by Adam.

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Rick Rosson 2014-9-11

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I think you want to loop over the number of columns in each matrix. So please try the following:

   for h=1:size(x,2)    
       for kb=1:size(z,2)

seprienna 2014-9-11

Rick,thanks for the tips. that is the result i'm looking for. thanks again.

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Adam 2014-9-11

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编辑：Adam 2014-9-11

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size(x)

will return a length d vector where d is the dimension of x. In your case that will be [882 2] and likewise size(y) will return [882 8].

If you want the first dimension you can use

size( x, 1 )

to give 882, or

size( x, 2 )

if you want the second dimension only. You can use

length(x)

if you just want the longest dimension but don't know what the index of that dimension is, but I don't recommend using length for this purpose if you do know which dimension you want.

That may not be the only problem, but it will definitely cause problems.