FFT in 3D matrix
显示 更早的评论
Hi all,
is there any pssibility wothout for loop to do the FFt of this:
F_domain = FFT (t_domain). t_domain is a matrix of 3D (800*10*200). the time axis is the First dimension (800). the second dimension is repetition of the Measurement. the Third dimens is the number of measurements.
Thank you all
采纳的回答
David Young
2014-9-12
I'm not quite sure what the second and third dimensions are, but assuming you want each column transformed on the time dimension, you would do this:
F_domain = fft(t_domain, [], 1);
2 个评论
Pascal Weller
2020-11-12
Hello,
I am currently facing the same question but did not fully get the answer. So I just wanted to get things clarified again.
I got a 3D (x,y,z) matrix. The first dimension (x) holds the samples per measurement, the second dimension (y) consecutive measurements and the third dimension (z) represents the number of channels that capture the individual measurements simultaneously. For every layer (xy-plane) I want to perform a FFT of size N on the columns. What would the right syntax be? Simply:
resultFFT = fft(3Dmatrix,N,1);
Thank you everyone for your input.
Pascal Weller
2020-11-18
Update: The syntax above is correct. It computes the FFT of size N on the columns for each layer individually.
更多回答（1 个）
deboleena sadhukhan
2023-3-13
0 个投票
Can you just try using fftn which will perform fft in all directions of the 3d matrix
类别
在 帮助中心 和 File Exchange 中查找有关 Fourier Analysis and Filtering 的更多信息
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!
Translated by 
