FFT in 3D matrix

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Rica
Rica 2014-9-12
回答： deboleena sadhukhan 2023-3-13
Hi all,
is there any pssibility wothout for loop to do the FFt of this:
F_domain = FFT (t_domain). t_domain is a matrix of 3D (800*10*200). the time axis is the First dimension (800). the second dimension is repetition of the Measurement. the Third dimens is the number of measurements.
Thank you all

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采纳的回答

David Young
David Young 2014-9-12
I'm not quite sure what the second and third dimensions are, but assuming you want each column transformed on the time dimension, you would do this:
F_domain = fft(t_domain, [], 1);
  2 个评论
Pascal Weller
Pascal Weller 2020-11-12
Hello,
I am currently facing the same question but did not fully get the answer. So I just wanted to get things clarified again.
I got a 3D (x,y,z) matrix. The first dimension (x) holds the samples per measurement, the second dimension (y) consecutive measurements and the third dimension (z) represents the number of channels that capture the individual measurements simultaneously. For every layer (xy-plane) I want to perform a FFT of size N on the columns. What would the right syntax be? Simply:
resultFFT = fft(3Dmatrix,N,1);
Thank you everyone for your input.
Pascal Weller
Pascal Weller 2020-11-18
Update: The syntax above is correct. It computes the FFT of size N on the columns for each layer individually.

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更多回答（1 个）

deboleena sadhukhan
Can you just try using fftn which will perform fft in all directions of the 3d matrix

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