First input argument must be a function handle
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Hello, Please!!!!! i need help. I'm trying to solve an integral function :
r=0:0.02:0.2;
d=[0.0005;0.001;0.0015;0.002;0.0025;0.003;0.0035;0.004;0.0045;0.005;0.0055];
fun={@(d,r) d.^3*exp(-4.1*(r.^(-0.21)*d))};
F=integral(fun,0.0005,0.0055);
But it returns : "First input argument must be a function handle"
Please how can i solve this problem?
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回答(2 个)
the cyclist
2014-9-13
编辑:the cyclist
2014-9-13
There were a couple problems here.
First, you put your function in side a cell array (with the curly brackets), which is unnecessary, and is why MATLAB did not recognize fun as a function handle.
Second, you seem to want to do a double integral, but you used integral() rather than integral2().
Third, your function definition used matrix multiplication rather than element-wise multiplication in a couple places.
The following code fixes all of these problems, but I can't say for sure is what you intended to do:
fun=@(d,r) d.^3.*exp(-4.1.*(r.^(-0.21).*d));
F=integral2(fun,0.0005,0.0055,0,0.2);
Note that your pre-definition of r and d vectors is going to be ignored by integral2(). These two lines will execute on their own.
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