Why does quatrotate() produce negative rotations?
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Code
% YPR angles to rotate
yaw = pi/4;
pitch = 0;
roll = 0;
% Point to rotate
A = [ 1 0 0]
% Rotate (Negative)
Q = angle2quat(yaw, pitch, roll);
B = quatrotate(Q, A)
% Rotate (Expected result)
Q = angle2quat(-yaw, -pitch, -roll);
C = quatrotate(Q, A)
Results:
A =
1 0 0
B =
0.7071 -0.7071 0
C =
0.7071 0.7071 0
0 个评论
采纳的回答
Mischa Kim
2014-9-19
Hello Dereck, there is a difference between a) rotating a reference frame (e.g. relative to a "fixed" vector) and b) rotating a vector relative to a reference frame. Check out this answer for reference.
angle2quat converts rotation angles [to quaternions]. Rotation angles in turn are used to rotate reference frames a), not vectors b). To illustrate, if you do not convert to quaternions but keep working with rotation angles and matrices you could do the same by computing the direction cosine matrix, DCM:
DCM = angle2dcm(yaw,pitch,roll)
DCM =
0.707106781186548 0.707106781186547 0
-0.707106781186547 0.707106781186548 0
0 0 1.000000000000000
rotate_Frame = DCM*A'
ans =
0.707106781186548
-0.707106781186547
0
which, as pointed out above, rotates the reference frame relative to the vector.
If you need to rotate the vector instead, use rotx and equivalent:
rotate_Vector = rotz(yaw*180/pi)*roty(pitch*180/pi)*rotx(roll*180/pi)*A'
ans =
0.707106781186547
0.707106781186547
0
3 个评论
Tamas Sarvary
2019-1-24
You could rotate your vectors by the inverse quaternion:
c = quatrotate(quatinv(Q), A)
James Tursa
2020-2-7
See also this post. The quatrotate function should probably use the phrase "coordinate system transformation" instead of the phrase "rotated vector".
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