I'm trying to compare components of an array using relational operators, and the outcome needs to be either true or false. My result is a row vector of logicals; how do i make sure the result is just a single 1 or 0?

2 次查看(过去 30 天)
A=rand(15,10); B=any(A(8,:))==max(A); B= 0 0 0 0 0 0 0 0 0 0

采纳的回答

Stephen23
Stephen23 2014-9-19
编辑:Stephen23 2014-9-19
Note that like many MALTAB functions, max , any and all work along one (default or specified) dimension. If you wish for these function to operate on every element in the array, then you can use the syntax (:), regardless of the size of the array, eg:
any(X(:))
So one solution for your code would be:
A = rand(15,10);
B = any(A(:)==max(A(:)));
Unless you need that (8,:) indexing for some other purpose...

更多回答(1 个)

Guillaume
Guillaume 2014-9-19
You've misplaced a bracket:
B=any(A(8,:) == max(A));
  2 个评论
Image Analyst
Image Analyst 2014-9-19
japna's "Answer" moved here:
Oh Sorry! I carried it out on the command window correctly, with the bracket in place, and the answer it is giving me is correct....i just don't know how to convert that row vector of logicals to a single 1 or 0
A=rand(15,10);
B=any(A(8,:))==max(A);
B= 0 0 0 0 0 0 0 0 0 0
Image Analyst
Image Analyst 2014-9-19
Guillaume's reply moved here:
Please comment on the answer rather than starting a new answer.
I meant to say, that for it to work, you need to move the bracket as I've shown in my answer. You get a scalar.
any (if you want true for at least one true) or all (if you require every element to be true) is what you use to transform a vector of logical to a scalar.

请先登录,再进行评论。

类别

Help CenterFile Exchange 中查找有关 Matrix Indexing 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by