Changing Cell Array Dimension
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Please I have a cell array as below but need it to be in 2 dimension, that is m-by-n instead of m-by-n-by-p.
segmented_images =
Columns 1 through 3
[2592x4608x3 unit8] [2592x4608x3 unit8] [2592x4608x3 unit8]
Columns 4 through 6
[2592x4608x3 unit8] [2592x4608x3 unit8] [2592x4608x3 unit8]
Thank you.
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the cyclist
2014-9-19
编辑：the cyclist
2014-9-19
Do you want each 3D array to remain inside its cell, as it is now? If so, I think your best bet is to use the cellfun() function, which will perform an operation on each cell of an array.
You can use the reshape() function (as the first argument to cellfun).
You want to look at the documentation for these two functions, and try them out separately to see what they do, before trying them both on your problem.
That being said, here is some code that works, to give you some idea of the syntax.
new_image = cellfun(@(x)reshape(x,2592*3,4608),segmented_images,'UniformOutput',false)
BUYER BEWARE: I don't know if this actually reshapes your images the way you intend to. You'll need to do some testing to confirm the output.
3 个评论
bayoishola20
2014-9-19
Pierre Benoit
2014-9-19
I think it will be best to ask another question for the use of the confusion matrix since it's totally unrelated to this question.
bayoishola20
2014-9-19
更多回答（1 个）
Image Analyst
2014-9-19
What you said makes no sense. It's a 1D cell array. You can reshape it into a 2D array with reshape
segmented_images = reshape(segmented_images, [m,n]);
Saying "m-by-n instead of m-by-n-by-p." is nonsense because, like I said, the cell array is 1 by 6 not "m-by-n-by-p". The contents of a cell array are independent of the dimensions of the cell array itself. Think of a cell array as an array of buckets, with each cell being one bucket. Now you can thrown whatever you want into any of the buckets: strings, 2D or 3D arrays, structures, tables, or whatever you want, but that doesn't affect the arrangement of the buckets (how many buckets there are or how many rows or columns of buckets there are). See the FAQ for a better explanation. http://matlab.wikia.com/wiki/FAQ#What_is_a_cell_array.3F
4 个评论
Image Analyst
2014-9-19
By the way, why is this tagged with "color segmentation"? I have demos for that in my File Exchange if you're interested: http://www.mathworks.com/matlabcentral/fileexchange/?term=authorid%3A31862
bayoishola20
2014-9-20
编辑：bayoishola20
2014-9-20
Image Analyst
2014-9-20
I don't have the Statistics Toolbox so I can't run kmeans.
bayoishola20
2014-9-20
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