How do I ifft two vectors?

Shaun Toner

2021 10 11

0 个回答

19 次查看（30 天）

0 个投票

This is the question:

Use fft() and ifft() functions provided by MATLAB, while X[k] = fft(x[n]).Compute the result for the following equations and plot the result. Describe your findings.

i)H1[k] =fft(h[n]), y[n] =ifft(X[k]H1[k])

ii)H2[k] =fft(h[n+ 12] +h[n] +h[n−12]), y[n] =ifft(X[k]H2[k])

iii)H3[k] =fft(h[n+ 5] +h[n] +h[n−5]), y[n] =ifft(X[k]H3[k])

How do I find y[n] in each of these, I have tried

ifft( (X[k])*(H1[k]))

and

ifft( (X[k]).*(H1[k]))

, but I get the error message, "Arrays have incompatible sizes for this operation." So how do i make them the same length and then appy that to the ifft.

Thank you!

1 个评论
显示 -1更早的评论隐藏 -1更早的评论

Image Analyst 2021-10-11

编辑：Image Analyst 2021-10-11

在 MATLAB Online 中打开

What does x[n] mean? You can't fft a single value, so is x a 2-D array and x[n] is the nth row or column of that array? You use parentheses to reference array indices in MATLAB, not square brackets. Square brackets are for creating matrices, not referencing elements from them. If you're using the whole matrix, then maybe you meant:

ft = ifft(x .* h1)

请先登录，再进行评论。

请先登录，再回答此问题。

Follow Question