mean without stable step

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Fani
Fani 2014-9-25
回答： Fani 2014-9-25
Hi all! I need your help please!
my data are 3033 lines and 2005 columns. I want to find the mean for all columns separately but the step in lines is different. For example, i want to find the mean for the first 167 lines, then from 168 to 294, 295 to 428 and so on. what code can i write?
Thank you!

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Fani
Fani 2014-9-25
This works perfect!!!
Thank you very much for your time!!!

更多回答（3 个）

Mikhail
Mikhail 2014-9-25
You can write a=mean(M,2) - this will find mean of matrix M along each column. And then take only values you need. For 3033*2005 this is ok.
  2 个评论
Mikhail
Mikhail 2014-9-25
Sorry, for columns use a=mean(M), or a=mean(M,1)
Mikhail
Mikhail 2014-9-25
Otherwise you can do it with for loop

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Fani
Fani 2014-9-25
In the same column the step is different. For example, in the first column i want to find mean for the first 167 lines, then from 168 to 294,295 to 459 and so on. And this for all columns.
  1 个评论
Mikhail
Mikhail 2014-9-25
ok, so you create vector containing number of lines you want to take: a=[1:167,168...].
If you want to take into account only this lines for all columns, you can make new matrix: N=M(a,:). The new matrix contains only lines you need. And use mean.

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Fani
Fani 2014-9-25
if i do this, i take mean for all these lines. I would like to take mean for 1:167, other mean for lines 168:294 and so on.

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