How to plot a function with 3 independent variables
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f(x,y,z)=0.95*x+0.73*y+0.62*z-130.05
f(x,y,z); x; y; and z are values between 0 and 100.
f(x,y,z) is shown in color. How can I plot in MATLAB similar to figure below.
Thank you!
1 个评论
Walter Roberson
2021-10-13
slice()
Or possibly isosurface() called several times
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KSSV
2021-10-13
f = @(x,y,z) 0.95*x+0.73*y+0.62*z-130.05 ;
x = linspace(0,100) ;
y = linspace(0,100) ;
z = linspace(0,100) ;
[X,Y,Z] = meshgrid(x,y,z) ;
V = f(X,Y,Z) ;
isosurface(X,Y,Z,V,1e-4)
6 个评论
Seng Hkawn N-Sang
2021-10-13
Thank you! This is really helpful. It does not work when the min and max for the variables are set to 60 and 100 and the upper and lower bounds for the V=f(x,y,z) are set to 70 and 100. How can I correct it?
I already have excel values for x,y,z, and f(x,y,z) in 4 columns where x in 1st column, y in 2nd, z in 3rd, and f(x,y,z) in 4th. How can I use excel data to plot in a similar plot in MATLAB?
No values as small as 1e-4 in the subset of the data.
f = @(x,y,z) 0.95*x+0.73*y+0.62*z-130.05 ;
x = linspace(60,100) ;
y = linspace(60,100) ;
z = linspace(60,100) ;
[X,Y,Z] = meshgrid(x,y,z) ;
V = f(X,Y,Z) ;
Vmin = min(V(:))
Vmax = max(V(:))
levels = 10:10:100;
Nlevels = length(levels);
for K = 1 : length(levels)
isosurface(X, Y, Z, V, levels(K));
end
xlim auto; ylim auto; zlim auto
view(3)
legend(string(levels))
Seng Hkawn N-Sang
2021-10-14
Thank you so much! Almost there!!!
Can you please let me know how I can add contour lines (at PCI=70,75,80,85,90,95,& 100)?
KSSV
2021-10-14
Replace levels with your required values.
f = @(x,y,z) 0.95*x+0.73*y+0.62*z-130.05 ;
x = linspace(60,100) ;
y = linspace(60,100) ;
z = linspace(60,100) ;
[X,Y,Z] = meshgrid(x,y,z) ;
V = f(X,Y,Z) ;
Vmin = min(V(:))
Vmax = max(V(:))
levels = 70:5:100;
Nlevels = length(levels);
cmap = hot(Nlevels);
for K = 1 : Nlevels
s = isosurface(X, Y, Z, V, levels(K));
p(K) = patch(s);
p(K).EdgeColor = 'none';
p(K).FaceColor = cmap(K,:);
isonormals(X, Y, Z, V, p(K));
end
camlight;
lighting gouraud;
xlim auto; ylim auto; zlim auto
view(3); view(36, 64);
legend(p, string(levels))
You cannot do contour lines because you are dealing with a 3D object: you can only do ISO surfaces.
It might be possible to get the colors right without some of the above steps. With the default steps I showed in https://www.mathworks.com/matlabcentral/answers/1562461-how-to-plot-a-function-with-3-independent-variables#comment_1783116 you might notice that the colors come out wrong compared to the legend: it turns out that you are looking at the "back" of the plates, and that you need to view() to see the front (or you need to move the light.)
Seng Hkawn N-Sang
2021-10-15
Thank you both!
Got it working!
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