how to find the angle subtended from origin to the poles in complex plane?

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Muhammad
Muhammad 2021-10-17
编辑： David Goodmanson 2021-10-17
Ran in:
clc
clear all
s=tf('s');
num=1;
den=(s+(-65+65j))*(s-(65+65j));
sys=num/den;
pzmap(sys)
i want to find the angle subtended by these poles from origin?

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采纳的回答

David Goodmanson
David Goodmanson 2021-10-17
编辑：David Goodmanson 2021-10-17
Hello Muhammed,
it's as easy as
angle(65+65j)
angle(65-65j)
with each angle in radians subtended from the x axis, -pi < angle <= pi

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