Remake this without a loop

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sznailc
sznailc 2021-10-17
编辑： DGM 2021-10-17
How to rewrite this without using a loop?
Basically I want to replace elements in matrix A with 0, that are equal to any of element in vector "vector"
vector = [A(A >= 1.5)].' % Vector, don't change.
for i = 1:vector
A(A == vector(i)) = 0;
end

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采纳的回答

the cyclist
the cyclist 2021-10-17
Ran in:
% Pretend data
A = 1 : 7;
vector = [2 3 5];
% Replace values of A with 0, if they are in vector
A(ismember(A,vector)) = 0
A = 1×7
1 0 0 4 0 6 7

更多回答（1 个）

DGM
DGM 2021-10-17
编辑：DGM 2021-10-17
What's wrong with just using the test you're already doing? In the case you've given, the vector is unnecessary.
A(A >= 1.5) = 0;
Or more generally, if you actually need to test against another set,
A = randi(5,5,8)
v = [3 4];
A(ismember(A,v)) = 0;

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