what changes are needed

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Manav Divekar
Manav Divekar 2021-10-17
评论： Star Strider 2021-10-17
accG2_A = C(:,1).*9.81;
forceG2_A = C(:,2).*0.00981;
dispG2_A = C(:,3)./1000;
time = dispG2_A./accG2_A;
s = smooth(forceG2_A);
%converted_values = findpeaks(converted_values);
%Force = converted_values(:,2);
plot (s);
how can i used this following data to plot the single cycle and not the following plot.
986 120 0
981 -60 0
984 -60 0
986 -70 0
993 -70 0
997 -70 0
1000 -70 0
1005 -70 0
1005 -70 0
1000 -70 0
994 -60 0
  2 个评论
Walter Roberson
Walter Roberson 2021-10-17
I have no idea how that data relates to that plot. The data has no value above 1005 (and has duplicate values in the first column). The data has nothing that appears to be in the range 0 to 16-ish. Your third column is all 0, so your time works out all 0.
Manav Divekar
Manav Divekar 2021-10-17
if you see the code i am just ploting the second column, and it is the only thing i want to plot. and the x axis is time. which is not needed to be specified. i am trying to think of login to compress the data so that i get only one curve

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回答（2 个）

Star Strider
Star Strider 2021-10-17
Ran in:
Try this —
F = openfig('Manav Divekar untitled.fig');
F.Visible = 'off'; % Don't Show Original
Ax = F.CurrentAxes;
x = Ax.Children.XData; % Get 'X'
y = Ax.Children.YData; % Get 'Y'
[Valleys,vlocs] = findpeaks(-y, 'MinPeakProminence',5); % Locate 'Valleys'
vlocs = [1 vlocs]; % Row Vector
Ts = mean(diff(x)); % Sampling Interval
for k = 1:numel(vlocs)-1
pkrng = vlocs(k) : vlocs(k+1); % Peak Rnage (Indices)
xr{k} = x(pkrng); % 'X' Values For Peak
yr{k} = y(pkrng); % 'Y' Values For Peak
end
np = numel(xr); % Number Of Peaks
nrows = 2; % Number Of Rows For Plot
figure
for k = 1:numel(xr)
subplot(nrows,fix(np/nrows),k)
plot(xr{k}, yr{k})
grid
title(sprintf('Peak #%d',k))
end
np = numel(xr);
maxx = max(cellfun(@numel,xr)); % Maximum Segment Length
ensemble = zeros(np,maxx); % Preallocate
for k = 1:np
ensemble(k,1:numel(yr{k})) = yr{k}; % Accumulate 'Y' Values For Each Peak
end
ensmean = mean(ensemble); % Calculate Ensemble Mean
ensstd = std(ensemble); % Ensemble Standard Deviation
enssem = ensstd/sqrt(np); % Ensemble Standard Error
tval = tinv([0.025 0.975],np-1); % t-Statistic For Confidence Intervals
figure
plot((1:maxx)*Ts, ensmean)
hold on
plot((1:maxx)*Ts, ensmean+tval(:)*enssem, ':k')
hold off
grid
xlabel('x')
ylabel('y')
title('Ensemble')
legend('Mean', '± 95% CI', 'Location','best')
Esperiment to get different results.
.
  4 个评论
显示 2更早的评论
Star Strider
Star Strider 2021-10-17
@Manav Divekar —
I did not see that you replaced the .fig file (originally) with a .txt file. (I have no idea when that occured.) The text file would have been easier for me to work with.
Nevertheless, I provided the requested information, including plots of the original peaks (choose which of them to plot if you only want to plot one) and an ensemble average of all of them, with relevant statisitics.
If my Answer helped you solve your problem, please Accept it!
.

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Walter Roberson
Walter Roberson 2021-10-17
Ran in:
filename = 'https://www.mathworks.com/matlabcentral/answers/uploaded_files/769961/G2_A.txt';
C = readmatrix(filename);
forceG2_A = C(:,2).*0.00981;
s = smooth(forceG2_A);
plot(s)
[~, idx] = findpeaks(s, 'MinPeakHeight', 6);
mid = floor(idx(1:end-1) + diff(idx)/2);
t1 = 1:mid(1);
s1 = s(t1);
t2 = mid(1)+1:mid(2);
s2 = s(t2);
plot(t1, s1, 'k*-', t2, s2, 'b+-')

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