A function does not work with an array as an input argument

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Bogdan MP
Bogdan MP 2021-10-22
评论： Bogdan MP 2021-10-22
I have the following function
MyFun = @(a, x) ( integral(@(k) k .* (1 ./ ( 1 + (a*k - x).^2 )), -1, 1) ./ ...
integral(@(k) 1 ./ ( 1 + (a*k - x).^2 ), -1, 1) );
Which is simply
I have a vector (or an array) of data x. Let's say x = 0 : 1 : 10; When I try to call MyFun(-1, x) I get a mistake ''matrix dimensions must agree''. Could you tell me please, how to fix that?

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Matt J
Matt J 2021-10-22
args={'ArrayValued',1};
MyFun = @(a, x) ( integral(@(k) k .* (1 ./ ( 1 + (a*k - x).^2 )), -1, 1,args{:}) ./ ...
integral(@(k) 1 ./ ( 1 + (a*k - x).^2 ), -1, 1,args{:}) )

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