Extract data from a web page

Question

Dimitrios Poulos 2021-10-23

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此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/1570278-extract-data-from-a-web-page

评论： Image Analyst 2021-10-24

I want to extract a specific number from a web page. To be more accurate the number 74. It is the cloud coverage from Windy page. This information exist in the following image at the tab elements but my code is extracting more ....general information(attachment). How I could extract this specific info from tab ''elements'' in chrome browser?

In the attachment there is my result from the following code but 74 does not exist. :-(

url = char(strcat({'https://www.windy.com/?clouds,2021-10-27-11,'},{MitraN},{','},{MitraE},{',8,d:picker'}));
options = weboptions('CertificateFilename','');
A1 = webread(url,options)

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Answer 1

Image Analyst 2021-10-23

0
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/1570278-extract-data-from-a-web-page#answer_814983

在 MATLAB Online 中打开

xml2struct.m

Try turning that imcomprehensible mess of XML into an organized structure with the attached function:

url = char(strcat({'https://www.windy.com/?clouds,2021-10-27-11,'},{MitraN},{','},{MitraE},{',8,d:picker'}));
options = weboptions('CertificateFilename','');
A1 = webread(url,options)
s = xml2struct(A1)

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Image Analyst 2021-10-24

We can't run your code because you did not define MitraN and MitraE. Tell us what those should be. Give us code that can run!

Image Analyst 2021-10-24

在 MATLAB Online 中打开

Why do you think "74" should exist in the returned string?

When you right click on the page and say View Source do you see a 74?

url = char('https://www.windy.com/?clouds,2021-10-27-11,23.1283199987984,-16.0439653616218,8,d:picker');
options = weboptions('CertificateFilename','');
A1 = webread(url,options)
index = strfind(A1, '74')
for k = 1 : 50 : length(A1)
    k2 = min(length(A1), k+49);
    fprintf('%s\n', A1(k:k2));
end