Extract first non-NaN of each row without loop

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Dave
Dave 2021-10-24
评论： Dave 2021-10-24
Hello, from a matrix where each row contains at least one non-NaN, is there away to extract the FIRST non-nan of each row without using a loop?
A=[NaN,444,NaN,NaN,41;
NaN,NaN,NaN,222,NaN;
NaN,NaN,554,554,NaN;
125,747,21,NaN,4;
NaN,NaN,NaN,43,NaN;
NaN,98,NaN,75,NaN;
NaN,22,NaN,NaN,NaN]
From matrix A, I would like to arrive to B
B=[444;222;554;125;43;98;22]
Thanks
  1 个评论
Dave
Dave 2021-10-24
编辑：Dave 2021-10-24
I am able to do it one row at a time, for example for the last row
A(7,find(~isnan(A(7,:)), 1, 'first'))
But without a loop I cannot do it for all rows

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采纳的回答

Walter Roberson
Walter Roberson 2021-10-24
Ran in:
A=[NaN,444,NaN,NaN,41;
NaN,NaN,NaN,222,NaN;
NaN,NaN,554,554,NaN;
125,747,21,NaN,4;
NaN,NaN,NaN,43,NaN;
NaN,98,NaN,75,NaN;
NaN,22,NaN,NaN,NaN]
A = 7×5
NaN 444 NaN NaN 41 NaN NaN NaN 222 NaN NaN NaN 554 554 NaN 125 747 21 NaN 4 NaN NaN NaN 43 NaN NaN 98 NaN 75 NaN NaN 22 NaN NaN NaN
B = A(sub2ind(size(A), (1:size(A,1)).', sum(cumprod(isnan(A),2),2)+1))
B = 7×1
444 222 554 125 43 98 22

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