How to get a geometric sequence?

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Grace
Grace 2014-10-2
编辑： Yokesh 2017-6-27
Hi, I have
tao=1000;
v=0.9;
T1=0.01;
I want to have a geometric sequence T, where T1=T2=T3...=T1000 ( since tao=1000)
The first 100 T will be equal to T1,
The second 100 T which starts from T101 until T200= v*T1
The third 100 T ( from T201 until T300 = v*v*T1)
The fourth 100 T (from T301 till T400 = v*v*v*T1)
and so on.
How am I going to get the sequence? Thanks in advance.
  1 个评论
Yokesh
Yokesh 2017-6-27
编辑：Yokesh 2017-6-27
A = r.^(1:n);
This creates matrix A with geometric sequence with a ratio 'r'

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回答（2 个）

SK
SK 2014-10-2
Use the .^ operator and matrix multiplication
T = v.^(0:9) * T1;
T = ones(100,1)*T;
T = T(:);
Alternatively (maybe faster)
T = v.^(0:9) * T1;
T = T(ones(1,100), :);
T = T(:);
the cyclist
the cyclist 2014-10-2
It was not perfectly clear to me what you needed to leave as a variable, and what is a constant. But, this should get you started.
v=0.9;
T1=0.01;
T = T1*ones(100,10);
v_vector = v.^(0:9);
T = bsxfun(@times,T,v_vector)
T = reshape(T,1,1000)

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