char array to cell array convert?
显示 更早的评论
T cell array
T = {[5.8882656], [0.01232356], [0.02556545],[0.035659595] , ...}
A = num2str(T,'%.2f');
A = '5.88 0.01 0.02 0.03 0.04 0.05'
A = str2num(A)
A = NaN
OUTPUT I WANT
A = { 5.88] ,[0.01],[0.02],[0.03],[0.04] , [0.05] }
2 个评论
T = {[5.8882656], [0.01232356], [0.02556545],[0.035659595]}
A = cellfun(@(x) str2num(num2str(x,'%.2f')), T)
Rik
2021-10-27
@Johan Pelloux-Prayer This looks like an answer. Please move it to the answer section.
A few notes: using cellfun is simply hiding the for loop (which is generally faster). You are also using str2num instead of str2double. str2num calls eval internally and can do a lot of damage if used with untrusted input. str2double has as downside that it will only works on scalars, but is otherwise completely safe to use (it will return NaN if it fails).
采纳的回答
If you want to round your data, just use round:
T = {[5.8882656], [0.01232356], [0.02556545],[0.035659595]};
T = cell2mat(T);
T = round(T,2);
T = num2cell(T)
You can ignore the trailing zeros when this data is displayed. You should distinguish the data itself and the way it is displayed in Matlab.
3 个评论
Divyesh pandav
2021-10-27
Rik
2021-10-27
What I mean by that is that it looks as if the numbers have 4 decimals, while we just rounded them to 2. The reality is that we rounded the values to the closest equivalent that can be represented in the internal binary storage system that Matlab uses.
When you see the output in the command window (or here just below the code), that internal representation is translated to a human readable form again.
Divyesh pandav
2021-10-30
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