char array to cell array convert?

2 次查看（过去 30 天）
Divyesh pandav
Divyesh pandav 2021-10-27
评论： Divyesh pandav 2021-10-30
T cell array
T = {[5.8882656], [0.01232356], [0.02556545],[0.035659595] , ...}
A = num2str(T,'%.2f');
A = '5.88 0.01 0.02 0.03 0.04 0.05'
A = str2num(A)
A = NaN
OUTPUT I WANT
A = { 5.88] ,[0.01],[0.02],[0.03],[0.04] , [0.05] }
  2 个评论
Johan
Johan 2021-10-27
Ran in:
T = {[5.8882656], [0.01232356], [0.02556545],[0.035659595]}
T = 1×4 cell array
{[5.8883]} {[0.0123]} {[0.0256]} {[0.0357]}
A = cellfun(@(x) str2num(num2str(x,'%.2f')), T)
A = 1×4
5.8900 0.0100 0.0300 0.0400
Rik
Rik 2021-10-27
@Johan Pelloux-Prayer This looks like an answer. Please move it to the answer section.
A few notes: using cellfun is simply hiding the for loop (which is generally faster). You are also using str2num instead of str2double. str2num calls eval internally and can do a lot of damage if used with untrusted input. str2double has as downside that it will only works on scalars, but is otherwise completely safe to use (it will return NaN if it fails).

请先登录，再进行评论。

请先登录，再回答此问题。

采纳的回答

Rik
Rik 2021-10-27
Ran in:
If you want to round your data, just use round:
T = {[5.8882656], [0.01232356], [0.02556545],[0.035659595]};
T = cell2mat(T);
T = round(T,2);
T = num2cell(T)
T = 1×4 cell array
{[5.8900]} {[0.0100]} {[0.0300]} {[0.0400]}
You can ignore the trailing zeros when this data is displayed. You should distinguish the data itself and the way it is displayed in Matlab.
  3 个评论
显示 1更早的评论
Rik
Rik 2021-10-27
What I mean by that is that it looks as if the numbers have 4 decimals, while we just rounded them to 2. The reality is that we rounded the values to the closest equivalent that can be represented in the internal binary storage system that Matlab uses.
When you see the output in the command window (or here just below the code), that internal representation is translated to a human readable form again.

请先登录，再进行评论。

更多回答（0 个）

类别

在 Help Center 和 File Exchange 中查找有关 Data Type Conversion 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by