stuck again with regular expression

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Max Müller
Max Müller 2014-10-5
评论： Azzi Abdelmalek 2014-10-5
Hey Guys, I want to get the Letter before the word CAMERA out of this String:
SHOT -31045 J CAMERA
I know i need to use regexp. I have create this code
regexp(str,'(SHOT)+\b+[0-9]+\b+(.*?)+\b(CAMERA)')
But It doesnt work. Can u help me ?
SHOT and CAMERA will always be the same. Only the NUMBER and the Letter before CAMERA can be different.

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回答（2 个）

Azzi Abdelmalek
Azzi Abdelmalek 2014-10-5
编辑：Azzi Abdelmalek 2014-10-5
str='SHOT -31045 J CAMERA'
out=regexp(str,'\S\s+(CAMERA)','match')
out=out{1}(1)
%or if there are many cases
str='SHOT -31045 J CAMERA k CAMERA'
out=regexp(str,'\S\s+(CAMERA)','match')
out=cellfun(@(x) x(1),out,'un',0)
  2 个评论
Max Müller
Max Müller 2014-10-5
Thanks and i Guess i understand what u did there. This code searches for the backspace or empty space before Camera und gives back the Word Camera + the Letter before the backspace/empty space ?
Azzi Abdelmalek
Azzi Abdelmalek 2014-10-5
Or
str='SHOT -31045 J CAMERA k CAMERA'
out=regexp(str,'\S(?=\sCAMERA)','match')

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Guillaume
Guillaume 2014-10-5
编辑：Guillaume 2014-10-5
Where did you get that regular expression from? It doesn't mean much with matlab's regexp engine (particularly the \b does not mean blank but backspace).
If you just want a single letter before CAMERA, you can just ignore everything before and the regular expression is just a letter ([A-Za-z] or just [A-Z] if just capital letters), plus at least one blank (\s+) plus camera:
s = 'SHOT -31045 J CAMERA';
letter = regexp(s, '([A-Za-z])\s+CAMERA', 'tokens', 'once')

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