Merging row elements into single numbers
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If you have the 3*3 matrix
C = [3 4 5
6 7 9
1 5 8]
and you want to change it to the 3*1 matrix
C = [345
679
158]
so that you can for example sort it in descending order of the rows, how would you do this? Thank you.
采纳的回答
Edit: Use Star Strider's answer. It's faster.
C = [3 4 5
6 7 9
1 5 8]
C = double(string(C).join(''))
3 个评论
Breaking it down:
C = [3 4 5
6 7 9
1 5 8] % The matrix
string(C) % String arrays are nice to work with
string(C).join('') % Mush the strings together with no delimiter between
C = double(string(C).join('')) % Cast the output back into a double array
Another approach —
C = [3 4 5
6 7 9
1 5 8]
C*10.^[2;1;0]
Just thought I’d add that for fun!
.
Chris
2021-10-31
Interesting. This was probably the most obvious method before strings? Easily generalized for an array of single-digit integers:
C*10.^[size(C,2)-1:-1:0]'
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