If condition for all elements of array
显示 更早的评论
for i=1:n-2
for j=i+2:n
k_arr=i+1:j-1
for counter = 1:length(k_arr)
k = k_arr(counter);
if all(w(k)<(w(i)+((w(j)-w(i))*(t(k)-t(i))/(t(j)-t(i)))))
A(i,j)=1;
A(j,i)=1;
else A(i,j)=0;
A(j,i)=0;
end
disp('cycle completed');
end
end
In output I am expecting 1 only when if condition is true for all elements from k_arr(array) but it is giving output 1 even single element of array satisfy the condition. Please help me
采纳的回答
Walter Roberson
2021-10-31
if all(w(k)<(w(i)+((w(j)-w(i))*(t(k)-t(i))/(t(j)-t(i)))))
You are indexing all variables there, and each time you are indexing with a scalar. Because of this, the part inside the all() is always a scalar result, so the all() is not doing anything useful for you there.
Now, if you were to do
for i=1:n-2
for j=i+2:n
k_arr=i+1:j-1
k = k_arr;
if all(w(k) < (w(i)+((w(j)-w(i))*(t(k)-t(i))/(t(j)-t(i)))))
A(i,j)=1;
A(j,i)=1;
else
A(i,j)=0;
A(j,i)=0;
end
end
end
3 个评论
Beeraiah Thonti
2021-10-31
Walter Roberson
2021-10-31
I predict that your w and your t do not have the same orientation.
for i=1:n-2
for j=i+2:n
k_arr=i+1:j-1
k = k_arr;
if all(reshape(w(k),[],1) < (w(i)+((w(j)-w(i))*(reshape(t(k),[],1)-t(i))/(t(j)-t(i)))))
A(i,j)=1;
A(j,i)=1;
else
A(i,j)=0;
A(j,i)=0;
end
end
end
Beeraiah Thonti
2021-10-31
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