Input struct in function
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When I try to run a function that needs constants defined in a struct outside of it, it give the error "Not enough input arguments.". How can I give as input in the function the data struct?
data.fluid.rho = 890;
data.accumulator.V_N2 = 10e-3;
data.accumulator.P_N2 = 2.5e6;
data.accumulator.p0 = 21e6;
data.accumulator.gamma = 1.2;
data.delivery.D23 = 1;
function dydt = problem(t,y,data)
A23 = (data.delivery.D23^2/4)*pi;
end
This is just an example with some line of codes, I get an error on A23, not enough input arguments. I suspect the function doesnt know what data.delivery.D23 is even if its written outside, how can I pass the data structure in the function?
3 个评论
"how can I pass the data structure in the function?"
t_in = ..
y_in = ..
data = ..
out = problem(t_in,y_in,data)
Note that your function returns one output argument dydt which is not defined anywhere inside the function.
Matt J
2021-10-31
The error is not caused by anything in the code you've shown us. It is caused by the code where problem() is actually invoked.
Nader Mohamed
2021-11-1
编辑：Nader Mohamed
2021-11-1
回答（1 个）
Sulaymon Eshkabilov
2021-10-31
data.fluid.rho = 890;
data.accumulator.V_N2 = 10e-3;
data.accumulator.P_N2 = 2.5e6;
data.accumulator.p0 = 21e6;
data.accumulator.gamma = 1.2;
data.delivery.D23 = 1;
% A few things are missing:
t = ... % initialize t
y = ... % initialize y
function dydt = problem(t,y,data)
A23 = (data.delivery.D23^2/4)*pi;
dydt = ... % Define dydt
end
2 个评论
Nader Mohamed
2021-11-1
Walter Roberson
2021-11-1
options = odeset('RelTol',1e-9,'AbsTol',1e-9,'Events',@event);
[tt,yy] = ode15s(@(t,y)problem(t,y,data),[t0,tf],[0,0,1e-3,data.accumulator.Vf],options);
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2021-10-31
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