3D surface issues HELP!

1 次查看(过去 30 天)
James
James 2014-10-7
评论: James 2014-10-7
  • * So these are the questions... most of the variables are fixed the long equation has been dramatically simplified in my code :) * *
  • | This is what mine looks like.. |
What it should look like...
This is my code...
% Q = theta
r = linspace(0,15,200);
Q = linspace(0,2*pi,200);
[r,Q] = meshgrid(r,Q);
w = 14.0591*(1-(r/15)^2)^2 + 15;
x = r.*cos(Q);
y = r.*sin(Q);
mesh(x,y,w)
What have I done wrong? Why isnt mine round, I dont think 'r' is being inputed into the 'w' equation correctly, HELP!

采纳的回答

Star Strider
Star Strider 2014-10-7
You need to vectorise your code and it will do just what you want:
r = linspace(0,15);
Q = linspace(0,2*pi);
[r,Q] = meshgrid(r,Q);
w = 14.0591*(1-(r/15).^2).^2 + 15;
x = r.*cos(Q);
y = r.*sin(Q);
mesh(x,y,w)
  9 个评论
Star Strider
Star Strider 2014-10-7
编辑:Star Strider 2014-10-7
My pleasure!
The sincerest expression of gratitude here on MATLAB Answers is to Accept the answer that most closely solves your problem.

请先登录,再进行评论。

更多回答(1 个)

Image Analyst
Image Analyst 2014-10-7
r is an array so you need .^ and not just ^. Try this:
workspace;
r = linspace(0,15,200);
Q = linspace(0,2*pi,200);
[r,Q] = meshgrid(r,Q);
w = 14.0591*(1-(r/15).^2).^2 + 15;
x = r.*cos(Q);
y = r.*sin(Q);
mesh(x,y,w)
% Enlarge figure to full screen.
set(gcf, 'Units', 'Normalized', 'OuterPosition', [0 0 1 1]);
  1 个评论
James
James 2014-10-7
编辑:James 2014-10-7
Thank you so much!
I have a few more questions: ALL GOOD NOW :)
  • I want it to be a surface plot, i did surfc(x,y,w) but i want specifically 10 countours, how do i make this happen?
  • And it is very black :S i want a nice range of colours, this is when i do a surface plot
(Both answers were fantastic, this is the same reply to the previous answer, feel free to help out some more :) )

请先登录,再进行评论。

类别

Help CenterFile Exchange 中查找有关 Surface and Mesh Plots 的更多信息

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by