i want to generalize and reduce following program into one loop

1 次查看（过去 30 天）
Mudasir Ahmed
Mudasir Ahmed 2014-10-7
评论： Mudasir Ahmed 2014-10-7
chx1=genx1 chx2=genx2 chx3=genx3 chx4=genx4 chx5=genx5
chy1=geny1 chy2=geny2 chy3=geny3 chy4=geny4 chy5=geny5
if ((gudx1>0) & (gudx2>0)) if (chx1==genx1) chx1= gudx2; end end
if ((gudx1>0) & (gudx3>0)) if (chx1==genx1) chx1= gudx3; end end
if ((gudx1>0) & (gudx4>0)) if (chx1==genx1) chx1= gudx4; end end
if ((gudx1>0) & (gudx5>0)) if (chx1==genx1) chx1= gudx5; end end
if ((gudx2>0) & (gudx3>0)) if (chx2==genx2) chx2= gudx3; end end
if ((gudx2>0) & (gudx4>0)) if (chx2==genx2) chx2= gudx4; end end
if ((gudx2>0) & (gudx5>0)) if (chx2==genx2) chx2= gudx5; end end
if ((gudx3>0) & (gudx4>0)) if (chx3==genx3) chx3=gudx4; end end
if ((gudx3>0) & (gudx5>0)) if (chx3==genx3) chx3=gudx5; end end
if ((gudx4>0) & (gudx5>0)) if (chx4==genx4) chx4= gudx5; end end
if ((gudx5>0) & (gudx1>0)) if (chx5==genx5) chx5= gudx1; end end
if ((gudx5>0) & (gudx2>0)) if (chx5==genx5) chx5= gudx2; end end
if ((gudx5>0) & (gudx3>0)) if (chx5==genx5) chx5= gudx3; end end
if ((gudx5>0) & (gudx4>0)) if (chx5==genx5) chx5= gudx4; end end
%y
if ((gudy1>0) & (gudy2>0)) if (chy1==geny1) chy1= gudy2; end end
if ((gudy1>0) & (gudy3>0)) if (chy1==geny1) chy1= gudy3; end end
if ((gudy1>0) & (gudy4>0)) if (chy1==geny1) chy1= gudy4; end end
if ((gudy1>0) & (gudy5>0)) if (chy1==geny1) chy1= gudy5; end end
if ((gudy2>0) & (gudy3>0)) if (chy2==geny2) chy2= gudy3; end end
if ((gudy2>0) & (gudy4>0)) if (chy2==geny2) chy2= gudy4; end end
if ((gudy2>0) & (gudy5>0)) if (chy2==geny2) chy2= gudy5; end end
if ((gudy3>0) & (gudy4>0)) if (chy3==geny3) chy3=gudy4; end end
if ((gudy3>0) & (gudy5>0)) if (chy3==geny3) chy3=gudy5; end end
if ((gudy4>0) & (gudy5>0)) if (chy4==geny4) chy4= gudy5; end end
if ((gudy5>0) & (gudy1>0)) if (chy5==geny5) chy5= gudy1; end end
if ((gudy5>0) & (gudy2>0)) if (chy5==geny5) chy5= gudy2; end end
if ((gudy5>0) & (gudy3>0)) if (chy5==geny5) chy5= gudy3; end end
if ((gudy5>0) & (gudy4>0)) if (chy5==geny5) chy5= gudy4; end end
ch1=[chx1 chy1] ch2=[chx2 chy2] ch3=[chx3 chy3] ch4=[chx4 chy4] ch5=[chx5 chy5]
i want to generalize above program and size of chx[1...5] and chy[1...5] may increase or decrease depend on user

请先登录，再回答此问题。

采纳的回答

José-Luis
José-Luis 2014-10-7
And this is a prime example of why you should store your variables in a single matrix instead of with "numbered" names.
So the answer would be:
Place all gudxn and gudyn in a single array and loop through that array instead.
gudx(1) = gudx1;
gudx(2) = gudx2;
Ad nauseam...
  4 个评论
显示 2更早的评论
José-Luis
José-Luis 2014-10-7
I'm sorry but I don't follow your logic. Are you testing for all possible permutations of gudx and gudy?
Mudasir Ahmed
Mudasir Ahmed 2014-10-7
A1=B1 A2=B2 A3=B3 A4=B4 A5=B5 %save values B in A
if ((X1>0) & (X2>0)) if (A1==B1) A1=X2; end end
if ((X1>0) & (X3>0)) if (A1==B1) A1=X3; end end
actually i want to pair in the following sense 1-2 1-3 1-4 1-5 2-3 2-4 2-5 3-4 3-5 4-5 5-1 5-2 5-3 5-4
pair with itself and decreasing one is not allowed except the final variable, who can pair with all variable below him except himself.
and 2nd main point is changing of any variable A1,A2,A3,A4,A5 is allowed only one time, means we cannot change a value of any variable twice or thrice.

请先登录，再进行评论。

更多回答（0 个）

类别

在 Help Center 和 File Exchange 中查找有关 Define Shallow Neural Network Architectures 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by