If Statement in a table

6 次查看（过去 30 天）
Noush
Noush 2021-11-2
评论： Noush 2021-11-3
I have the table K below and would like to use an if statement that replaces the zeros in the fifth column with 300, everytime that the row one below contains a "Ja".
My if statement looks like this:
if K(i,2:5)=="Ja"
K(i-1,6) = 300
end
This is the error I get: Index in position 1 is invalid. Array indices must be positive integers or logical values.
What do I need to change to access the correct data?
Thank you for your help!

请先登录，再回答此问题。

回答（1 个）

Cris LaPierre
Cris LaPierre 2021-11-2
Ran in:
Have you defined i? If not, it is sqrt(-1).
There error means i is either a decimal or negative number.
A=1:3;
% Works
A(2)
ans = 2
% doesn't work
A(1.5)
Array indices must be positive integers or logical values.
  3 个评论
显示 1更早的评论
Cris LaPierre
Cris LaPierre 2021-11-3
When indexing a table, paretheses return a table while curly braces return an array. You need to use curly braces to extract the value from the table.
You can read more about accessing data in tables here.
Noush
Noush 2021-11-3
thank you, this fixed my problem :)

请先登录，再进行评论。

类别

在 Help Center 和 File Exchange 中查找有关 Tables 的更多信息

标签

产品


版本

R2020a

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by