Local Binary Pattern(LBP)

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C N N 2011-9-13

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此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/15774-local-binary-pattern-lbp

评论： Image Analyst 2023-7-16

I am trying to execute local binary pattern in MATLAB using the image processing toolbox. When i execute I can't get a LBP image and LBP histogram.

clear all;
close all;
clc;
I=imread('test.png');
figure,imshow(I)
%%Crop
I2 = imcrop(I);
figure, imshow(I2)
w=size(I2,1);
h=size(I2,2);
%%LBP
scale = 2.^[7 6 5; 0 -inf 4; 1 2 3];
for i=2:w-1
    for j=2:h-1
        J0=I2(i,j);
        I3(i-1,j-1)=I2(i-1,j-1)>J0;
        I3(i-1,j)=I2(i-1,j)>J0;
        I3(i-1,j+1)=I2(i-1,j+1)>J0;
        I3(i,j+1)=I2(i,j+1)>J0;
        I3(i+1,j+1)=I2(i+1,j+1)>J0;
        I3(i+1,j)=I2(i+1,j)>J0;
        I3(i+1,j-1)=I2(i+1,j-1)>J0;
        I3(i,j-1)=I2(i,j-1)>J0;
        LBP(i,j)=I3(i-1,j-1)*2^7+I3(i-1,j)*2^6+I3(i-1,j+1)*2^5+I3(i,j+1)*2^4+I3(i+1,j+1)*2^3+I3(i+1,j)*2^2+I3(i+1,j-1)*2^1+I3(i,j-1)*2^0;
    end
end
figure,imshow(LBP)
figure,imhist(LBP)

what is the issue.i am supposed to get numbers from 0 to 255 but i am not getting it. how to correct it?

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Image Analyst 2019-2-3

在 MATLAB Online 中打开

localBinaryPattern.m

Try

imshow(LBP, []);

and try my attached LBP demo.

sajjad nasiri 2019-5-28

download and see this:

https://www.mathworks.com/matlabcentral/mlc-downloads/downloads/7ba8e802-dc16-4710-a57d-88797dcd6d94/bd092fd4-c4aa-4510-b49d-96a18fa6f739/packages/zip

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回答（10 个）

madhulika jain 2011-9-22

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https://ww2.mathworks.cn/matlabcentral/answers/15774-local-binary-pattern-lbp#answer_22226

I think you shpuld be getting LBP in the range 0 to 255. I ran this code and i got the values in this range only

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C N N 2011-9-22

The problem with this code that after you get LBP, you need to convert it to uint8 before displaying it.

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Izzo 2011-12-3

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https://ww2.mathworks.cn/matlabcentral/answers/15774-local-binary-pattern-lbp#answer_30152

在 MATLAB Online 中打开

hey i think i got your problem, because i already did LBP. First, make sure that u have converted the image into grayscale form. Second, you have to replace the test image with the new LBP image, therefore: instead of this code

LBP(i,j)=I3(i-1,j-1)*2^7+I3(i-1,j)*2^6+I3(i-1,j+1)*2^5+I3(i,j+1)*2^4+I3(i+1,j+1)*2^3+I3(i+1,j)*2^2+I3(i+1,j-1)*2^1+I3(i,j-1)*2^0;

try to change into:

I2(i-1,j-1)=I3(i-1,j-1)*2^7+I3(i-1,j)*2^6+I3(i-1,j+1)*2^5+I3(i,j+1)*2^4+I3(i+1,j+1)*2^3+I3(i+1,j)*2^2+I3(i+1,j-1)*2^1+I3(i,j-1)*2^0;

because i have problem like that too, then my supervisor solve into this for me :P

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Image Analyst 2011-9-22

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https://ww2.mathworks.cn/matlabcentral/answers/15774-local-binary-pattern-lbp#answer_22292

在 MATLAB Online 中打开

Change the last few lines of your code to this:

    subplot(2,2,3);
    imshow(LBP, []);
    subplot(2,2,4);
    [pixelCounts, GLs] = imhist(uint8(LBP));
    bar(GLs, pixelCounts);

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Fatemeh Shomal Zadeh 2021-2-13

在 MATLAB Online 中打开

Hi,

I have a cell array data of grayscale images 20x5. (20 images at 5 frames)

I want to use LBP to analyze the background scatter points of my images and see if I can find any differences between their values, as my data covers the healthy and unhealthy patients.

Is there anyone who can help me for that. I have been using this code;

features = extractLBPFeatures(images{20,1})
subplot(2,2,3);
imshow(features, []);
subplot(2,2,4);
[pixelCounts, GLs] = imhist(uint8(features));
bar(GLs, pixelCounts);

But I think it does not show me what I want. As the output is a single array. I am not very familiar with LBP, can you please hep me regarding how the output should be?

Walter Roberson 2021-2-14

But I think it does not show me what I want

We do not have your image to test with, and we do not know what kinds of output you expect to see.

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remo 2011-12-1

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https://ww2.mathworks.cn/matlabcentral/answers/15774-local-binary-pattern-lbp#answer_30002

hi CNN,

Sorry for being a Noob. I just cant understand why you use 'scale = 2.^[7 6 5; 0 -inf 4; 1 2 3]; ' in this program. can you explain?

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Muhammad Amirul Hafiz Sahful Bahri 2019-3-29

hi, I would like to know how did you get those number [ 7 6 5; 0 -inf 4; 1 2 3] ?

Did you calculate it?

Image Analyst 2019-3-29

localBinaryPattern.m

Unhide the comments above and you'll see a desciption of how those are computed.

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anusha 2014-9-24

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链接

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https://ww2.mathworks.cn/matlabcentral/answers/15774-local-binary-pattern-lbp#answer_152714

编辑：DGM 2023-2-11

在 MATLAB Online 中打开

u can try this code

clear all; 
close all; 
I=imread('cameraman.tif'); 
I=rgb2gray(I); 
I1=imcrop(I); 
[w h]=size(I1);
for i=2:w-1 
    for j=2:h-1 
        val=I1(i,j); 
        scale=2.^[0 1 2;7 -inf 3;6 5 4]; 
        mat=[I1(i-1,j-1) I1(i-1,j) I1(i-1,j+1);
             I1(i,j-1) I1(i,j) I1(i,j+1);
             I1(i+1,j-1) I1(i+1,j) I1(i+1,j+1)]; 
        mat=mat>=val; 
        fin=mat.*scale; 
        I1(i,j)=sum(sum(fin)); 
    end
end
imshow(I1,[]);