Unable to perform assignment because the size of the left side is 1-by-1 and the size of the right side is 1-by-2
1 次查看(过去 30 天)
显示 更早的评论
Xindex = zeros(217,2);
Xval = zeros(201,1,217);
for index = 1:217
Xval(:,1,index) = A(:,3,index);
for rowidx = 1:201
if(Xval(rowidx,1,index)>7.227 && Xval(rowidx,1,index)<7.2510)
r = 1;
c = 1;
Xindex(r, c) = [index rowidx];
r = r + 1;
c = c + 1;
end
end
end
The underlined code is causing the error. I am not sure what is wrong as Xindex has 217 rows and 2 columns, I am trying to fit two values alongside each other in the same row. Why is a size mismatch occuring?
Please help, thanks in advance!
0 个评论
采纳的回答
James Tursa
2021-11-3
编辑:James Tursa
2021-11-3
Does this do what you want:
Xindex(r, :) = [index rowidx];
You can get rid of c altogether since it isn't needed. And you need to move the r = 1 line to up above the start of the for loops.
更多回答(0 个)
另请参阅
类别
在 Help Center 和 File Exchange 中查找有关 Matrix Indexing 的更多信息
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!