Pythagorean triples - wrong output in loop

1 次查看(过去 30 天)
Hello, I have this piece of code, it computes pythagorean triples, then adds them in a matrix, but in output for some reason it adds lines with zeros. How do I change the code to run properly?
And 1 more thing how to make it print sorted by a+b+c column, not by a like now?
UPD. I have solved 1 part of the question with "R = reshape(nonzeros(R), I, 4);
"
function [R, I] = pyth_tri(N)
I = 0;
for a = 3:N/3
for b = a:N/3
for c = b:N
if (a^2 + b^2) == c^2 && a ~= 0 && b ~= 0 && c ~= 0
R(a, :) = [a+b+c, a, b, c]
I = I + 1;
end
end
end
end
end

采纳的回答

the cyclist
the cyclist 2021-11-3
You need
R(I+1, :) = [a+b+c, a, b, c];
rather than
R(a, :) = [a+b+c, a, b, c];
For sorting, after your run your algorithm, run
R = sortrows(R,1)

更多回答(0 个)

类别

Help CenterFile Exchange 中查找有关 Operating on Diagonal Matrices 的更多信息

产品


版本

R2021a

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by