Standard deviation of 2D array

Hi,
I am trying to calculate the standard deviation of 2D array 'v' of dimesnion 89 x 97.
I have tried as follows ,but it returns the output in the form of 1 x 97 instread of 89 x 97. Could someone help me with this
V1 = std (v);

 采纳的回答

Star Strider
Star Strider 2021-11-6

0 个投票

The standard deviation of a scalar is 0 so the result is —
standard_deviation_v = zeros(size(v))
in this instance.
.

4 个评论

Hi,
Thanks I just checked. Though it yields results in 89 x 97 array, however, all the standard deviation values are zero..
As they should be.
The standard deviations are valid and non-zero if taken across rows or columns (on in a multidmiensional array, a specific dimension).
Calculating the standard deivation across the third dimension here (so each individual scalar) produces —
v = rand(89,97)
v = 89×97
0.3176 0.4743 0.4498 0.2482 0.4525 0.6837 0.4908 0.2914 0.9379 0.1937 0.6850 0.5043 0.2961 0.2275 0.7154 0.2022 0.0023 0.9774 0.0146 0.9340 0.9574 0.3732 0.7484 0.0872 0.1360 0.5074 0.5602 0.8739 0.0030 0.5378 0.2584 0.1894 0.3723 0.9644 0.0514 0.3840 0.5639 0.4938 0.4834 0.4695 0.6003 0.3930 0.9223 0.2461 0.2159 0.4884 0.8516 0.6950 0.9837 0.4972 0.1860 0.1820 0.2270 0.2164 0.3897 0.0965 0.4047 0.9546 0.3066 0.9510 0.0362 0.5856 0.0955 0.1356 0.7095 0.5816 0.1061 0.9346 0.1909 0.4830 0.9627 0.5205 0.6587 0.7511 0.4202 0.0762 0.2718 0.0027 0.5365 0.9341 0.5114 0.1364 0.6142 0.8989 0.0643 0.5395 0.2587 0.3957 0.8722 0.8927 0.5580 0.9194 0.7983 0.8412 0.5769 0.8895 0.3469 0.0505 0.1800 0.6799 0.4938 0.5923 0.2852 0.6942 0.6023 0.3313 0.9509 0.0939 0.5642 0.8119 0.9132 0.2708 0.7792 0.8428 0.6634 0.7914 0.1808 0.4120 0.7127 0.8783 0.5743 0.9389 0.4356 0.2958 0.1456 0.0101 0.0334 0.3761 0.0551 0.5322 0.4195 0.3785 0.6602 0.7843 0.1021 0.5288 0.5701 0.9108 0.1013 0.9304 0.1100 0.1890 0.4810 0.9255 0.3429 0.0091 0.4485 0.1633 0.5688 0.0930 0.4730 0.7792 0.0324 0.9049 0.0409 0.9804 0.1001 0.6882 0.8350 0.0176 0.9968 0.2064 0.1408 0.8134 0.8692 0.8671 0.8323 0.2955 0.8186 0.3277 0.0561 0.5148 0.4377 0.1855 0.2647 0.1639 0.6836 0.6931 0.5509 0.3950 0.6487 0.9884 0.9817 0.3008 0.0589 0.3406 0.1499 0.7129 0.7021 0.3067 0.5540 0.4717 0.2021 0.3025 0.2733 0.4091 0.8190 0.3141 0.4931 0.2977 0.8817 0.4532 0.0145 0.5354 0.9743 0.0855 0.2653 0.3339 0.8514 0.1727 0.8610 0.7541 0.0731 0.5767 0.3492 0.6835 0.5188 0.1462 0.9584 0.1433 0.8594 0.1973 0.6940 0.7562 0.7208 0.4494 0.9059 0.5781 0.0174 0.8602 0.1506 0.9939 0.0943 0.9477 0.7425 0.5248 0.5851 0.8669 0.0807 0.4423 0.4303 0.6783 0.5461 0.7124 0.7804 0.7018 0.6898 0.6771 0.7743 0.1767 0.4670 0.4155 0.8837 0.0245 0.7318 0.0056 0.4344 0.6394 0.6097 0.7438 0.0043 0.3886 0.8524 0.8176 0.8685 0.8124 0.8072 0.6733 0.3688 0.1457 0.6304 0.3754 0.7873 0.5024 0.5350 0.9765 0.5470 0.0514 0.9915 0.1818 0.8456 0.2711 0.0711 0.3204 0.8498 0.2127 0.4112 0.8229 0.8036 0.5223 0.8232 0.9784 0.7524 0.1801 0.7947 0.7446 0.5634 0.7837 0.1725 0.1128
standard_deviation_v = std(v,[],3)
standard_deviation_v = 89×97
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
This is of course the expected result.
.
Ok, I will look into this..

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