Hello everyone.
I have a vector with times called
tim1_1
, of size 51*1, I also have measurements called
lam1_1
made at those times.
tim1_1
goes between 0 and 1.737857815507103e+03. Instead of 51 measurements I want to have an arbitrary number, let's say 200. I have tried to write
interpLam1_1R = interp1(tim1_1,lam1_1,1:tim1_1(end)/200:tim1_1(end),'spline');
Unfortunately, if I plot the obtained results, they don't look like the original ones at all. As can be seen in the attached figure, the original data (in blue) looks almost sinusoidal,meanwhile, the interpolated data looks almost as a straight line.
Can someone please help me with this problem?

 采纳的回答

Apparently ‘tim1_1’ is not a datetime array.
tim1_1 = linspace(0, 1.737857815507103e+03, 51);
lam_1 = sin(2*pi*1E-3*tim1_1);
tim1_2 = linspace(min(tim1_1), max(tim1_1), 200);
lam_1_2 = interp1(tim1_1, lam_1, tim1_2);
figure
plot(tim1_1, lam_1, '.b')
hold on
plot(tim1_2, lam_1_2, '.r')
hold off
grid
legend('Original','Interpolated', 'Location','best')
Experiment to get different results.
.

2 个评论

Thanks, I think I can work with this.
As always, my pleasure!
.

请先登录,再进行评论。

更多回答(0 个)

类别

帮助中心File Exchange 中查找有关 Logical 的更多信息

产品

版本

R2021b

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by