how can i obtain this?

Question

RADWAN A F ZEYADI 2021-11-8

0
链接

此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/1581789-how-can-i-obtain-this

编辑： Cris LaPierre 2021-11-8

HI

ihave data with dimension 153*1 and i want to perform for loop in order to obtain 153*71 where 71 is position along horiziontal axis but i tried to perform it and i got 153*71 but duplicated rows and columns and this is doesnt make sense so how is it linspace function useful for this?

3 个评论
显示 1更早的评论隐藏 1更早的评论

RADWAN A F ZEYADI 2021-11-8

i have obtained from % d_pred = reshape(d_pred(:,1,:),[],1,1);%convert data from 3d to column vector

RADWAN A F ZEYADI 2021-11-8

it was 51 71 3

请先登录，再进行评论。

请先登录，再回答此问题。

Answer 1

Cris LaPierre 2021-11-8

0
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/1581789-how-can-i-obtain-this#answer_826744

编辑：Cris LaPierre 2021-11-8

在 MATLAB Online 中打开

You have not shared your code so it's a little challenging to say what is happening, but if I were to start with a 51x71x3 matrix, and wanted to change it to 153x71, where each column is all the data in the indicated column across all 'sheets', I'd use permute then reshape.

d_pred = rand(51,71,3);
D_pred = permute(d_pred,[1 3 2]);
D_Pred = reshape(D_pred,153,[]);
size(D_Pred)
ans = 1×2
   153    71

0 个评论
显示 -2更早的评论隐藏 -2更早的评论

请先登录，再进行评论。

Answer 2

DGM 2021-11-8

0
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/1581789-how-can-i-obtain-this#answer_826749

编辑：DGM 2021-11-8

在 MATLAB Online 中打开

I'm assuming that you want all 71 columns to be extracted in the same fashion. Consider the example:

% 5x5x3 array
A = cat(3,reshape(1:25,5,5),reshape(101:125,5,5),reshape(201:225,5,5))
A = 
A(:,:,1) =

   6    11    16    21
   7    12    17    22
   8    13    18    23
   9    14    19    24
  10    15    20    25


A(:,:,2) =

 106   111   116   121
 107   112   117   122
 108   113   118   123
 109   114   119   124
 110   115   120   125


A(:,:,3) =

 206   211   216   221
 207   212   217   222
 208   213   218   223
 209   214   219   224
 210   215   220   225
B = reshape(permute(A,[1 3 2]),[],size(A,2),1) % 15x5 array
B = 15×5
   6    11    16    21
   7    12    17    22
   8    13    18    23
   9    14    19    24
  10    15    20    25
 106   111   116   121
 107   112   117   122
 108   113   118   123
 109   114   119   124
 110   115   120   125