Neural Network Script to have Specific Testing Data from Inputs.

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Richard 2014-10-12

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评论： Richard 2014-10-19

Hello everyone,

I have been trying to write a neural network script that uses DivideInd to train my neural network. I'm using all the data for my input as the training and validating data for the neural network, however for the testing data I am using only the initial third of the data. However when I run the script, I run into the issue of,

??? Undefined function or method 'patternnet' for input arguments of type 'double'.

My code is as shown below, and yes I have made sure to be in the working directory when I run the script so that is not the issue.

inputs = Hand_Data_Inputs;
targets = Hand_Data_Targets;

% Create a Pattern Recognition Network

hiddenLayerSize = 31;
net = patternnet(hiddenLayerSize);

% Set up Division of Data for Training, Validation, Testing

net.divideFcn = 'divideInd';
net.divideParam.trainInd = 1:3000;
net.divideParam.valInd = 1:3000;
net.divideParam.testInd = 1:1000;

% Train the Network

[net,tr] = train(net,inputs,targets);

% Test the Network

outputs = net(inputs);
errors = gsubtract(targets,outputs);
performance = perform(net,targets,outputs);

Any help would be greatly appreciated, thank you

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Richard 2014-10-12

在 MATLAB Online 中打开

Hmmmmmm, I typed

which patternnet -all

and it came up as,

'patternet' not found.

Star Strider 2014-10-12

If you have the Neural Network Toolbox installed (I assume you do), see if my Answer solves the problem.

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Answer 1

Greg Heath 2014-10-13

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Your data division makes no sense.

Although the trn, val, and tst subsets can overlap in space, they should not contain common points.

total = design + test

design = train + val

train: estimate weights

val: stops training when performance on NONTRAINING val subset reaches a local optimum. However, resulting nontraining performance estimate is biased because validation is part of the design

test: yields UNBIASED estimate of performance on unseen nontraining data

Hope this helps

Thank you for formally accepting my answer *

Greg

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Richard 2014-10-19

在 MATLAB Online 中打开

Okay I think I understand this fairly well except for what you mean by RNG, are you referring to the Random Number Generator function?

Also I have been training the neural network and only just realised that my network outputs the test performance with the NaN value. Not sure why and also does that mean that my neural network is not actually doing a test of the dataset to see whether it is accurate or not.

I've made little changes to the code as follows.

inputs = Hand_Data_Inputs;
targets = Hand_Data_Targets;
% Create a Pattern Recognition Network
hiddenLayerSize = 22;
net = patternnet(hiddenLayerSize);
% Choose Input and Output Pre/Post-Processing Functions
net.inputs{1}.processFcns = {'removeconstantrows','mapminmax'};
net.outputs{2}.processFcns = {'removeconstantrows','mapminmax'};
% Setup Division of Data for Training, Validation, Testing
net.divideFcn = 'divideind';  % Divide data randomly
net.divideMode = 'sample';  % Divide up every sample
net.divideParam.trainInd = 1:2:3000;
net.divideParam.valInd = 2:2:2999;
net.divideParam.testInd = 3:2:2998;
% For a list of all training functions type: help nntrain
net.trainFcn = 'trainlm';  % Levenberg-Marquardt
% Choose a Performance Function
net.performFcn = 'mse';  % Mean squared error
% Choose Plot Functions
net.plotFcns = {'plotperform','plottrainstate','ploterrhist', ...
  'plotregression', 'plotfit'};
% Train the Network
[net,tr] = train(net,inputs,targets);
% Test the Network
outputs = net(inputs);
errors = gsubtract(targets,outputs);
performance = perform(net,targets,outputs)
% Recalculate Training, Validation and Test Performance
trainTargets = targets .* tr.trainMask{1};
valTargets = targets  .* tr.valMask{1};
testTargets = targets  .* tr.testMask{1};
trainPerformance = perform(net,trainTargets,outputs)
valPerformance = perform(net,valTargets,outputs)
testPerformance = perform(net,testTargets,outputs)

Richard 2014-10-19

Just had a check of tr and realised that the test index doesn't appear declared. Not too sure as to why this is happening

Richard 2014-10-19

Again thank you for all the help you have provided so far Professor Heath

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