Numerical integration over a variable

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Özgür Alaydin
Özgür Alaydin 2021-11-10
回答： Walter Roberson 2021-11-10
Ran in:
Hello all
I have a function as given below and i want to integrate it over a variable but i am getting answer "V1=0".
However V1 can not be equal to "0" .
What is wrong?
Vb=0.450; dz=1e-10;
Ltot = 20e-9;
z=-Ltot/2:dz:Ltot/2;
L = 10e-9; a=2e-9; x=-L/2:dz/2:L/2;
f=Vb.*real(x./sqrt(a^2-(x-z).^2));
V1=trapz(~isnan(f),x)
V1 = 0

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Walter Roberson
Walter Roberson 2021-11-10
trapz(x, y) is the syntax. If isnan is either always true or is never true for f then the "x" coordinates would all be the same (all true or all false, and in that case, the output would be mean() of the "y" coordinates. But your "y" coordinates are your x variable and that happens to be symmetrical around zero, so the mean is zero and your result is 0

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