I want to find the position of cells with a specific content, but the empty cells are not counted, so I take a wrong result of position

Question

Ioannis Vourvachakis 2021-11-11

评论： Star Strider 2021-11-11

I have the cell array a.

This cell array is a 1603 * 1 cell array .

I want to find the cells that contain 'svinw to ena zeugos', so this is what I did:

b=find(ismember([a{:,1}],{'svinw to ena zeugos'}));

But the rows that are empty (only contain [] ) are not counted, so the array b finds wrong rows that contain 'svinw to ena zeugos'.

What can I do?

Answer 1

Star Strider 2021-11-11

The ‘b’ variable will contain the numeric indices from the logical vector that ismember returns, so ‘a{b,1}’ should return the desired results.

Lv = randi([0 1], 1, 10) == 1
Lv = 1×10 logical array
   0   0   0   1   0   0   0   0   1   1
Nv = find((Lv))
Nv = 1×3
     4     9    10

.

编辑：Ioannis Vourvachakis 2021-11-11

Τhe problem I describe is the following:

If I write b=ismember([a{:,1}],{'svinw to ena zeugos'});

b is a 1*1268 logical array, not the same dimensions as the array a.

This is happening because in array a the empty cells ( only contain [] ) are not counted.

I want the array b to have the same dimensions as array a.

The cell array a seems like

Star Strider 2021-11-11

Posting (uploading) the file would be helpful.