Stacking multiple arrays into a matrix
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How can i form a matrix out of n number of different column matrices of same size by placing them side by side.
采纳的回答
You can make append two columns like this:
a=rand(10,1);
b=rand(10,1);
c=[a b];
size(c)
or like this:
c=cat(2,a,b);
size(c)
Both approaches extend to n columns:
a=rand(10,1);
b=rand(10,1);
c=rand(10,1);
d=rand(10,1);
M1=[a b c d];
size(M1)
M2=cat(2,a,b,c,d);
size(M2)
Alternatively, you could initialize a matrix and then fill it with the columns:
M3=nan(numel(a),4); % you don't really need to initialize, but it is wise
M3(:,1) = a;
M3(:,2) = b;
M3(:,3) = c;
M3(:,4) = d;
size(M3)
6 个评论
HEMRAJ PATEL
2021-11-13
Image Analyst
2021-11-13
@HEMRAJ PATEL surely they don't all have unique names though. You don't have 2000 separately named individual variables do you, because that would be a disaster.
HEMRAJ PATEL
2021-11-13
Where do c1, c2, etc come from? Can you create them as a matrix to begin with? How are they identified? is it all variables in the workspace that begin with the letter c?
In theory, you could create a statement like the one above using eval...but as @Image Analyst if you have 2000 separately named variables that sounds like a disaster, and if you're using the variable name to indicate column identity that's probably also not great.
Stephen23
2021-11-13
"if i have 2000 matrices like (c1,c2,c3,...,c2000) and i want them in cat function. How will i do it."
I have some ideas of how you might do it, but no experienced MATLAB users would do that.
"Do i have to write c=cat(2,c1,c2,c3....) or do we have another option"
Another option is better data design: don't have numbered variable names.
Numbered variable names is a sign that you are doing something wrong. Use indexing instead.
HEMRAJ PATEL
2021-11-13
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