number of elements of each unique values in a matrix

43 次查看（过去 30 天）
Christopher
Christopher 2014-10-15
评论： Sean de Wolski 2014-10-15
I can use unique(A) to get an array of each unique value in the matrix A. However, how can I also get an array of the number of elements with each unique value? For instance
B=unique(A) might give:
[1; 4; 6; 8];
and an additional step might give:
[10; 1; 5; 7];
if there were 10 entries of 1, 1 entry of 4, 5 entries of 6, etc.
I know I can easily do this by doing find(A==B(1,1))... etc. but if the array of uniques is long then this should be very inefficient.
Is there a function like unique which returns the number of elements for each unique value without much additional computation??
Thanks

请先登录，再回答此问题。

采纳的回答

Andrei Bobrov
Andrei Bobrov 2014-10-15
B = unique(A);
out = [B,histc(A,B)];
  3 个评论
显示 1更早的评论
Sean de Wolski
Sean de Wolski 2014-10-15
A = [1;1;1;2;3;3];
B = unique(A);
out = [B,histc(A,B)]
out =
1 3
2 1
3 2
First column is value, second is number of occurrences

请先登录，再进行评论。

更多回答（0 个）

类别

在 Help Center 和 File Exchange 中查找有关 Logical 的更多信息

标签

产品

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by