Derive base 10 logarithm from base 2 log output

11 次查看（过去 30 天）
Life is Wonderful
Life is Wonderful 2021-11-15
评论： Life is Wonderful 2021-11-15
Ran in:
Hi
I am looking to calculate .
  • log10 with base2log as input.i.e. log10(log2())
  • log() with base2log as input i.e. log(log2())
I have only base2log function available for calculation and I don't have common log() and log10() available
Below is my code and I am looking for the right mathematical formula for conversion so that I can get equivalent log() and log10() using log2()
Thank you!!
input = 32;
b = log2(input);
constant = 2.30258509299405; % assuming log(10)
base10 = log(b) / (constant) % formula for conversion, I don't have log function available
base10 = 0.6990
output = log10(b)
output = 0.6990
nlog = log(input) % need conversion formula
nlog = 3.4657
nlog = log(32)/log(2.718281828)
nlog = 3.4657

请先登录，再回答此问题。

采纳的回答

Chunru
Chunru 2021-11-15
The formula is:
For any given base b, you need to compute a constant .

更多回答（0 个）

类别

在 Help Center 和 File Exchange 中查找有关 Argument Definitions 的更多信息

标签

产品


版本

R2021b

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by