How to convert hours, minutes, seconds to seconds?

69 次查看（过去 30 天）
Lizan
Lizan 2014-10-16
编辑： Stephen23 2023-8-21
Hi,
How can I return an array with
hh:min:sec
into
seconds?
For example
VarName2(1:5)
ans =
'14:54:25'
'14:54:25'
'14:54:25'
'14:54:26'
'14:54:26'
into a array with seconds?

请先登录，再回答此问题。

采纳的回答

Daniel
Daniel 2014-10-16
Assuming you mean seconds in the day
% initialize variables
NUM_SECONDS_PER_DAY = 86400.0;
timeStrings = {'14:54:25';'14:54:25';'14:54:25';'14:54:26';'14:54:26'};
% convert times to fractional days using datenum
timeFractionalDays = datenum(timeStrings);
% leave only the part with the most recent day fraction
timeDayFraction = mod(timeFractionalDays,1);
% multiply by number of seconds in a day
timeInSeconds = timeDayFraction .* NUM_SECONDS_PER_DAY
This produces the result
timeInSeconds =
1.0e+04 *
5.3665
5.3665
5.3665
5.3666
5.3666
  8 个评论
显示 6更早的评论
Daniel
Daniel 2014-10-16
Simply subtract the first value of the answer vector from itself.
% initialize variables
NUM_SECONDS_PER_DAY = 86400.0;
% convert times to fractional days using datenum
timeFractionalDays = datenum(VarName2);
% leave only the part with the most recent day fraction
timeDayFraction = mod(timeFractionalDays,1);
% multiply by number of seconds in a day
timeInSeconds = timeDayFraction .* NUM_SECONDS_PER_DAY;
% find answer starting from first value
timeInSeconds = timeInSeconds - timeInSeconds(1)

请先登录，再进行评论。

更多回答（1 个）

Stephen23
Stephen23 2023-8-21
编辑：Stephen23 2023-8-21
Ran in:
The approach for MATLAB >=R2014b is to use the DURATION class, e.g.:
C = {'14:54:25'; '14:54:25'; '14:54:25'; '14:54:26'; '14:54:26'};
S = seconds(duration(C))
S = 5×1
53665 53665 53665 53666 53666

类别

在 Help Center 和 File Exchange 中查找有关 Dates and Time 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by