Standalone Application Crash with infinite timer

Giovanna Scaramuzzino

2021 11 17

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HI,

i tried to create a standalone application with the code below. This code run in matlab ide, but when i start the .exe file created by application compiler tool this crash.

If i put a pause() function after parfeval() (into for) this crash after the execution of the pause function.

How can I solve the problem and what is it due to?

Thank you

delete(gcp('nocreate'));
p = parpool('local');
for i = 1:5
   futures(i) = parfeval(@provatimer,0,i);   
end
function provatimer(i)
    tic
    t = timer('TimerFcn',@(~,~)f('timer_parfeval_' + string(i)));
    t.ExecutionMode = 'fixedspacing';
    t.Period = 4;
    start(t);
    
end
function f(i)
    fileID = fopen( i + '.txt','at');
    fprintf(fileID,'%f \n',toc);
    fclose(fileID);
end

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Giovanna Scaramuzzino 2021-11-22

编辑：Giovanna Scaramuzzino 2021-11-22

在 MATLAB Online 中打开

The code run without error in Matlab, (writes endlessly in the files created) .

Using the file .exe this code crashes: files are created and the first value is written, after it crashes. I cant' post the .exe file but I create this with the Standalone Application tool of Matlab.

writing the code with pause(inf) :

for i = 1:5
   futures(i) = parfeval(@provatimer,0,i);  
end
pause(inf)

the code run also in .exe mode. This practise (use Pause(inf)) i don't think is correct.

Giovanna Scaramuzzino 2021-11-24

Before terminate the execution on the Windows Command shell the last phrase is : parallel pool using the local profile is shutting down (this appear only when execute the same code using the file .exe) and then the process terminate.

Why is possible?

I also tried to use parpool('local', 'IdleTimeout',Inf)

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