repmat usage for cellarray

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sermet OGUTCU
sermet OGUTCU 2021-11-18
回答: Jan 2021-11-18
data = 32 x 1
double_array=[repmat(data,1,286);]; %= 286 x 32 double
Now, I need to replace data with data_string as follows:
data_string = 32 x 3 char aray
Then, I need to create cell array using the above repmat operation. I tried the below but it gave error:
cell_array=repmat({data_string,1,286});
What is the proper way to construct cell_array matrix? My matlab version is 2019a.

采纳的回答

Jan
Jan 2021-11-18
If this is what you want:
cell_array = PG01 PG02 PG03 . . . PG32
PG01 PG02 PG03 . . . PG32
. . . . . . PG32
use:
cell_array = repmat(sprintf('PG%02d', 1:32), 286, 1)
In your call:
cell_array=repmat({data_string,1,286});
you provide a cell as input of repmat. But then the number of repetitions are missing. Mayby you mean:
cell_array=repmat(data_string, 1, 286);

更多回答(1 个)

Chunru
Chunru 2021-11-18
data_string = reshape(char(32:127), 3, []) % some characters32 x 3 char aray
data_string = 3×32 char array
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cell_array=repmat({data_string},1,3)
cell_array = 1×3 cell array
{3×32 char} {3×32 char} {3×32 char}
cell_array{3}
ans = 3×32 char array
' #&),/258;>ADGJMPSVY\_behknqtwz}' '!$'*-0369<?BEHKNQTWZ]`cfilorux{~' '"%(+.147:=@CFILORUX[^adgjmpsvy|'
  1 个评论
sermet OGUTCU
sermet OGUTCU 2021-11-18
编辑:sermet OGUTCU 2021-11-18
Dear @Chunru, your codes didn't produce the result it should when using my data:
data=[1:1:32];
double_array= 1 2 3 . . . 32
1 2 3 . . . 32
. . . . . . .
1 2 3 . . . 32 == 286 x 32 double (after [repmat(data,1,286);]; )
data_string =
32×3 char array
'G01'
'G02'
'G03'
.
.
'G32'
So after the last repmat operation, cell_array should be:
cell_array = PG01 PG02 PG03 . . . PG32
PG01 PG02 PG03 . . . PG32
. . . . . . PG32

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