Surface Animation from For Loop Help

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Luke Malone
Luke Malone 2021-11-21
评论： Image Analyst 2021-11-22
Ran in:
Hi, I am trying to create a surface that changes over time by using a for loop. I want this to be a plane surface that changes orientation by the values in the arrays I have set for x and y. I cannot seem to get an animation to be made after trying several techniques found online. Here is my current code, thanks in advance.
% Lat for test
x = [0 0.018000 0.0330 0.0410 0.0490 0.0550 0.0640 0.0760 0.0960];
% Long for test
y = [0 0.1520 0.20 0.180 0.1880 0.2270 0.2820 0.3380 0.3880];
g = 1;
Slope = [];
for i = 2:length(x) % Go through data one step at a time until through all data
% Slope must change each time with different x value
Slope(i) = (x(i) - x(i-1))/(y(i) - y(i-1));
end
ynew = Slope.*x;
for i = 1:length(Slope)
figure(1)
surf([x; x], [ynew(1,:); ynew(1,:)], [zeros(size(x)); ones(size(x))]); % Surface attempting to be moved
end
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Image Analyst
Image Analyst 2021-11-21
Luke, try to run the code before posting. We can't run that code. It gets to the time line and then says it doesn't know what T is.
Luke Malone
Luke Malone 2021-11-21
My bad, I didn't know that you could run the code in the browser, I just tested it here now and it seems to work.

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回答（1 个）

Image Analyst
Image Analyst 2021-11-21
编辑：Image Analyst 2021-11-21
In your loop, this does not change
[ynew(1,:); ynew(1,:)]
Nothing in that depends on "i" so your surface looks the same at every iteration.
And put in
drawnow;
pause(1);
at the end of your loop so you can see each individual surface.
  2 个评论
Luke Malone
Luke Malone 2021-11-21
I tried using,
surf([x(i); x(i)], [ynew(i)(1,:); ynew(i)(1,:)], [zeros(size(x)); ones(size(x))]);
But this didn't work either. Where should I put the (i) dependecy?
Image Analyst
Image Analyst 2021-11-22
Do you actually HAVE a surface? Or just an x and y vector? You might need to make a surface with scatteredInterpolant before you can call surf. See attached demo.

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