cut of zeros from a matrix based on the longest non-zero row

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Nikolas Spiliopoulos
评论： Dave B 2021-11-22
Hi all,
I want to cut all zeros from the right, based on "the longest non zero row". an example:
A=[ 1 2 0 0 0 0;3 4 5 0 0 0;5 6 0 0 0 0];
output: A=[ 1 2 0 ;3 4 5 ;5 6 0 ];
thanks in advance!

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Dave B
Dave B 2021-11-22
编辑：Dave B 2021-11-22
Ran in:
Another way to phrase this question is to say you want to remove columns from the right side of the matrix if the whole column is zeros:
A=[ 1 2 0 0 0 0;3 4 5 0 0 0;5 6 0 0 0 0];
lastnonzero=find(any(A~=0,1),1,'last') % the last column with a non-zero row
lastnonzero = 3
A(:,lastnonzero+1:end)=[]
A = 3×3
1 2 0 3 4 5 5 6 0
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Net Fre
Net Fre 2021-11-22
OK, much better than mine :)
Didn't know about any. Notice that your code will ingore non-zero negatives.
Dave B
Dave B 2021-11-22
oops, I updated to be ~=0, thanks for catching that! (technically it can just be any(A), but I find that specifying the condition explicitly is more readable)
any and all are very useful! they also take a dimension arg, or the keyword 'all' which I use often.

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Net Fre
Net Fre 2021-11-22
编辑：Net Fre 2021-11-22
Hi
You can use the cumprod function.
your code line can look like this:
% a = some matrix
idx = max(sum(cumprod(a~=0,2)),2)
output = a(:,1:idx)
I suggest you break the one line into several ones just to see what each function does.
hope this helps.

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