rotating contourf in r2014b

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How to rotate contours generated using contourf command in MATLAB R2014b?
rotating using get(gca, 'Children') doesn't seem to work.
  1 个评论
Ben11
Ben11 2014-10-20
do you mean actually rotating the data or something like 'rotate3d on'?

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采纳的回答

Mike Garrity
Mike Garrity 2014-10-20
Sean's right. The rotate command only works on a few types of objects, and you probably want to try hgtransform instead.
That would look something like this:
g = hgtransform
contourf(peaks,'Parent',g)
set(g,'Matrix',makehgtform('zrotate',pi/3))

更多回答(1 个)

Sean de Wolski
Sean de Wolski 2014-10-20
What do you mean by rotate?
>>rotate3d on
Still works.
In R2014b, contour is no longer a collection of patches but rather a contour plot object. If you look at it's properties, you might find what you want:
[c,h] = contourf(Z,10);
>> h
h =
Contour with properties:
LineColor: [0 0 0]
LineStyle: '-'
LineWidth: 0.5000
Fill: 'on'
LevelList: [-6.3605 -5.0954 -3.8302 -2.5651 -1.2999 -0.0348 1.2304 2.4955 3.7606 5.0258 6.2909]
XData: [1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20]
YData: [1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20]
ZData: [20x20 double]
Show all properties
  2 个评论
Venkatessh
Venkatessh 2014-10-20
Does this imply that the rotation of the contours had to be done numerically? I don't want to do it interactively such as using the
rotate3d on
since there are other plotted overlaid in the same figure.
Sean de Wolski
Sean de Wolski 2014-10-20
I'm not clear on what you mean by rotating. Whether it's interactive or programmatic, the whole figure will rotate. If you mean rotate the individual color patches relative to the rest of the figure, then you might want to look into using hgtransform.

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