Removing a particular legend from plot
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clear all
clc
k1=0.7;
k2=01;
wf=1;
ws=1.5;
b=0.15;
d=0.15;
a=0.15;
h=0.05;
j=0;
l=0;
ns1=0;
ns2=0;
nu=0;
for Zf= 0.01:0.01:1.5
n=0;
zf=Zf;
u7=-pi;
u5=pi*(wf^2 + 2*zf*(a + h)*wf + ws^2 + a*h + 1);
u3=(-pi*(wf^2*(ws^2 + a*h + 1) - k1*k2 + ws^2 + 2*wf*zf*(h*ws^2 + a)));
u2=8*b*d*wf*ws^2*zf;
u1=pi*(wf^2*ws^2 - k1*k2*ws^2);
v6=pi*(a + h + 2*wf*zf);
v4=(-pi*(a + wf^2*(a + h) + h*ws^2 + 2*wf*zf*(ws^2 + a*h + 1)));
v3=4*b*d*ws^2;
v2=pi*(wf^2*(h*ws^2 + a) + 2*wf*ws^2*zf - a*k1*k2);
v1=(-4*b*d*wf^2*ws^2);
j4=v3*u7;
j3=v3*u5+v1*u7-u2*v6;
j2=v3*u3+v1*u5-u2*v4;
j1=v3*u1+v1*u3-u2*v2;
j0=v1*u1;
j=[j4 j3 j2 j1 j0];
jr=roots(j);
w=jr.^0.5;
for i=1:size(w)
if imag(w(i,1))==0
o=w(i,1);
A=-u2*o^2/(u7*o^7+u5*o^5+u3*o^3+u1*o);
if A>0
d1=6*A*pi*(a + h + 2*wf*zf)*o^5 + (-4*A*pi*(a + wf^2*(a + h) + h*ws^2 + 2*wf*zf*(ws^2 + a*h + 1)))*o^3 + 12*b*d*ws^2*o^2 + 2*A*pi*(wf^2*(h*ws^2 + a) + 2*wf*ws^2*zf - a*k1*k2)*o - 4*b*d*wf^2*ws^2;
d2=- pi*o^7 + pi*(wf^2 + 2*zf*(a + h)*wf + ws^2 + a*h + 1)*o^5 - pi*(wf^2*(ws^2 + a*h + 1) - k1*k2 + ws^2 + 2*wf*zf*(h*ws^2 + a))*o^3 + pi*(wf^2*ws^2 - k1*k2*ws^2)*o;
d3=(-7*pi*A)*o^6 + 5*A*pi*(wf^2 + 2*zf*(a + h)*wf + ws^2 + a*h + 1)*o^4 + (-3*A*pi*(wf^2*(ws^2 + a*h + 1) - k1*k2 + ws^2 + 2*wf*zf*(h*ws^2 + a)))*o^2 + 16*b*d*wf*ws^2*zf*o + pi*A*(wf^2*ws^2 - k1*k2*ws^2);
d4=pi*(a + h + 2*wf*zf)*o^6 - pi*(a + wf^2*(a + h) + h*ws^2 + 2*wf*zf*(ws^2 + a*h + 1))*o^4 + pi*(wf^2*(h*ws^2 + a) + 2*wf*ws^2*zf - a*k1*k2)*o^2;
D=d1*d2-d3*d4;
l=l+1;
R(l,1)=A;
R(l,2)=o;
R(l,3)=D/abs(D);
end
end
end
R=sortrows(R,-1);
for k=1:size(R,1)
if R(k,3)==1
n=n+1;
if n==1;
ns1=ns1+1;
As1(ns1)=R(k,1);
Zfs1(ns1)=zf;
elseif n==2
ns2=ns2+1;
As2(ns2)=R(k,1);
Zfs2(ns2)=zf;
end
end
if R(k,3)==-1
nu=nu+1;
Au(nu)=R(k,1);
Zfu(nu)=zf;
end
end
R=0;l=0;
end
if ns1>0
plot(Zfs1,As1,'-k')
hold on
end
if ns2>0
plot(Zfs2,As2,'-k')
hold on
end
if nu>0
plot(Zfu,Au,':k')
end
legend
You can see the plot data 1 and data 2 are ploted with same property of line therefore i want to rmove the legend even the legend mark from data 2
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