Sorting numbers randomly in a specified range without changing their positions
3 次查看(过去 30 天)
显示 更早的评论
A = [5 8 8 4 0 0 10 10 2 2];
Since A is in the range of 1:10, I want to sort A such that all the repeated numbers are replaced with numbers that hasn't appeared yet within 1 to 10, slotting those numbers in, randomly, without ascending or descending. All their initial positions should be maintained without changing. All zeros will also be replaced with non-zeros in this specified range. Maybe to get a result like below.
Ans = [5 8 1 4 7 3 10 6 9 2];
0 个评论
采纳的回答
the cyclist
2021-11-26
% Input
A = [5 8 8 4 0 0 10 10 2 2];
% Find the pool of numbers that are available to fill
% (because they don't appear in A, but are in 1:10, in this case)
pool = setdiff(1:numel(A),unique(A));
% Find the locations to place the numbers
% (i.e. repeats and zeros)
loc = (diff([NaN A]) == 0) | (A==0);
% Fill the locations randomly from the pool
A(loc) = pool(randperm(numel(pool)))
12 个评论
更多回答(0 个)
另请参阅
类别
在 Help Center 和 File Exchange 中查找有关 Creating and Concatenating Matrices 的更多信息
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!