Feedin vector in feedback function for mimo systems

3 次查看(过去 30 天)
The documentation for the feedback function shows the following graph to indicate the connections between the plant and the controller.
From the figure, i assume that the feedin vector should be feedin=[4,2] because the 4th input of the plant is connected to the first ouput of the controller and the 2nd input of the plant to the 2nd output of the controller. But in the documentation they do feedin=[2 4]. In the example they shown random state space so only god knows if the result is as expected... Can anyone confirm the correct use of this function in a MIMO system?

采纳的回答

Paul
Paul 2021-11-26
Try an example with a known solution.
A = -diag(1:4); B = eye(4); C = eye(4); D = zeros(4);
sysp = ss(A,B,C,D);
sysk = ss(diag([5 10]));
feedout = [2 4];
feedin = [2 4];
sysc = feedback(sysp,sysk,feedin,feedout,-1);
tf(sysc)
ans = From input 1 to output... 1 1: ----- s + 1 2: 0 3: 0 4: 0 From input 2 to output... 1: 0 1 2: ----- s + 7 3: 0 4: 0 From input 3 to output... 1: 0 2: 0 1 3: ----- s + 3 4: 0 From input 4 to output... 1: 0 2: 0 3: 0 1 4: ------ s + 14 Continuous-time transfer function.
As you expected, the first output of sysk is mapped to the feedin(1) input to sysp and the second output of sysk is mapped to the feedin(2) input to sysp.

更多回答(0 个)

类别

Help CenterFile Exchange 中查找有关 Dynamic System Models 的更多信息

产品


版本

R2021b

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by