Integration with arbitrary constant
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Question 1 : I want to intgerate f(x)=x-a where a is some artitrary constant
I use the MATLAB code
fun=(2) x-a
ans=intgeral(fun,0,1)
But this code is showing the error due to arbitary constant .I also tried by mentioning syms a .But still error exist.
Question 2: Usng the following code i generated the series solution for k=1:11
series1(x,t)=simplify(series1(x,t)+U(k)*(power(t,k-1)));
series2(x,t)=simplify(series2(x,t)+V(k)*(power(t,k-1)));
end
series1
series2
C1=zeros(1);
C2=zeros(1);
for x=1:11:101
e=(x-1);
for t=1:5:31
f=(t-1)/10;
C1(x,t)=series1(e,f);
end
end
vpa(C1,15)
The answer are displayed, but it is displayed in the different form you can check the attachment. I want continous values.
3 个评论
Image Analyst
2021-11-27
What we get is
Invalid expression. Check for missing multiplication operator, missing or unbalanced delimiters, or other syntax error. To construct matrices,
use brackets instead of parentheses.
Your fun line is not correct syntax.
Also, the code you gave never defines a value for "a". What did you assign to a, and where did you do that assignment?
Please give the actual code you used.
It depends if you want to do this numerically or symbolically
% symbolically
syms x a
f = x-a;
int(f,0,1) % answer is a function of a
% numerically
a = 0; % have to define a
f = @(x) x-a;
integral(f,0,1) % answer is just a constant
The second part with the series stuff, I don't know, since half the code is missing.
Image Analyst
2021-11-27
Probably right @DGM, so you should put it in the Answers section below so he can accept it to award you reputation points for it. @YOGESHWARI PATEL, click "Show older comments" to see his answer.
采纳的回答
It depends if you want to do this numerically or symbolically
% symbolically
syms x a
f = x-a;
int(f,0,1) % answer is a function of a
% numerically
a = 0; % have to define a
f = @(x) x-a;
integral(f,0,1) % answer is just a constant
The second part with the series stuff, I don't know, since half the code is missing.
6 个评论
YOGESHWARI PATEL
2021-11-27
DGM
2021-11-27
What is series1?
YOGESHWARI PATEL
2021-11-28
DGM
2021-11-28
Where is it defined?
YOGESHWARI PATEL
2021-11-28
DGM
2021-11-28
The comment above and the original post are the only places where the variable 'series1' is mentioned.
syms x t
for k=1:10
U(k)=(-x)^k-1/(factorial(k))
end
for k=1:9
series1(x,t)=simplify(series1(x,t)+U(k)*(power(t,k-1)));
end
% ...
Here, series1 is used before it's defined. If you're trying to do something with symbolic functions, you might by over my head, but all I know is that this throws an error.
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