Converting a 2d array into a 3d array

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Hi,
I am having a 2d array with size mxn
I want to convert each column into a seperate 2d diagonal matrix--- a total of 'n' diagonal matrices of size mxm
Then combining all the 2d diagonal matrices as a single 3d matrix.---size mxmxn
I tried to do this with employing a for-loop but it is taking lot of time
Can this be done without using a loop and at a faster speed?
  2 个评论
Turlough Hughes
Turlough Hughes 2021-11-28
Can you give an example of the code you have implemented?
Vinay Killamsetty
Vinay Killamsetty 2021-11-28
编辑:Vinay Killamsetty 2021-11-28
size of Z_int is mxn
Z = nan(m,m,n)
for i = 1 : size( Z_int , 2)
Z( : , : , i ) = diag( (Z_int( :, i ) ) ;
end

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回答(2 个)

Chunru
Chunru 2021-11-28
"it is taking lot of time" for what size of array?
m=200; n=100;
Z_int = rand(m, n);
Z = nan(m,m,n);
tic
for i = 1 : size( Z_int , 2)
Z( : , : , i ) = diag( Z_int( :, i ) );
end
toc
Elapsed time is 0.009776 seconds.

Turlough Hughes
Turlough Hughes 2021-11-28
You could write a linear index for the diagonal elements as follows:
[m,n] = size(Z_int)
Z = zeros(m,m,n);
idx = repmat((1:m+1:m^2).',1,n) + m^2*(0:n-1);
Z(idx(:)) = Z_int(:)
This is 2-4x faster for m >= 400 on my computer (n=500), however, on the matlab servers its a slightly slower. Whether it's faster or not for you will depend on your hardware, the size of your arrays and probably the version of matlab that you're using too.

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